Certification Problem

Input (TPDB SRS_Standard/Waldmann_19/random-383)

The rewrite relation of the following TRS is considered.

b(b(a(a(x1))))	→	a(b(a(a(x1))))	(1)
b(a(a(a(x1))))	→	a(a(b(a(x1))))	(2)
a(a(a(a(x1))))	→	b(a(b(a(x1))))	(3)

Property / Task

Prove or disprove termination.

Answer / Result

Yes.

Proof (by NaTT @ termCOMP 2023)

1 Dependency Pair Transformation

The following set of initial dependency pairs has been identified.

b^#(a(a(a(x1))))	→	a^#(b(a(x1)))	(4)
a^#(a(a(a(x1))))	→	b^#(a(x1))	(5)
b^#(b(a(a(x1))))	→	a^#(b(a(a(x1))))	(6)
a^#(a(a(a(x1))))	→	a^#(b(a(x1)))	(7)
b^#(a(a(a(x1))))	→	b^#(a(x1))	(8)
b^#(a(a(a(x1))))	→	a^#(a(b(a(x1))))	(9)
a^#(a(a(a(x1))))	→	b^#(a(b(a(x1))))	(10)

1.1 Dependency Graph Processor

The dependency pairs are split into 1 component.

The 1^st component contains the pair

a^#(a(a(a(x1))))	→	b^#(a(b(a(x1))))	(10)
b^#(a(a(a(x1))))	→	a^#(a(b(a(x1))))	(9)
b^#(a(a(a(x1))))	→	b^#(a(x1))	(8)
a^#(a(a(a(x1))))	→	b^#(a(x1))	(5)
a^#(a(a(a(x1))))	→	a^#(b(a(x1)))	(7)
b^#(b(a(a(x1))))	→	a^#(b(a(a(x1))))	(6)
b^#(a(a(a(x1))))	→	a^#(b(a(x1)))	(4)

1.1.1 Reduction Pair Processor with Usable Rules

Using the Max-polynomial interpretation

[a(x₁)]	=	x₁ + 1
[b(x₁)]	=	x₁ + 1
[a^#(x₁)]	=	x₁ + 0
[b^#(x₁)]	=	x₁ + 0

together with the usable rules

b(b(a(a(x1))))	→	a(b(a(a(x1))))	(1)
a(a(a(a(x1))))	→	b(a(b(a(x1))))	(3)
b(a(a(a(x1))))	→	a(a(b(a(x1))))	(2)

(w.r.t. the implicit argument filter of the reduction pair), the pairs

b^#(a(a(a(x1))))	→	b^#(a(x1))	(8)
a^#(a(a(a(x1))))	→	b^#(a(x1))	(5)
a^#(a(a(a(x1))))	→	a^#(b(a(x1)))	(7)
b^#(a(a(a(x1))))	→	a^#(b(a(x1)))	(4)

could be deleted.

1.1.1.1 Dependency Graph Processor

The dependency pairs are split into 1 component.

The 1^st component contains the pair

b^#(b(a(a(x1))))	→	a^#(b(a(a(x1))))	(6)
a^#(a(a(a(x1))))	→	b^#(a(b(a(x1))))	(10)
b^#(a(a(a(x1))))	→	a^#(a(b(a(x1))))	(9)

1.1.1.1.1 Reduction Pair Processor with Usable Rules

Using the matrix interpretations of dimension 2 with strict dimension 1 over the naturals

[a(x₁)]

0	1
0	1

· x₁ +

1837

[b(x₁)]

0	1
1	0

· x₁ +

[a^#(x₁)]

1	0
1	0

· x₁ +

[b^#(x₁)]

1	0
1	0

· x₁ +

together with the usable rules

b(b(a(a(x1))))	→	a(b(a(a(x1))))	(1)
a(a(a(a(x1))))	→	b(a(b(a(x1))))	(3)
b(a(a(a(x1))))	→	a(a(b(a(x1))))	(2)

(w.r.t. the implicit argument filter of the reduction pair), the pairs

b^#(b(a(a(x1))))	→	a^#(b(a(a(x1))))	(6)
a^#(a(a(a(x1))))	→	b^#(a(b(a(x1))))	(10)
b^#(a(a(a(x1))))	→	a^#(a(b(a(x1))))	(9)

could be deleted.

1.1.1.1.1.1 Dependency Graph Processor

The dependency pairs are split into 0 components.