The rewrite relation of the following TRS is considered.
b(a(a(b(x1)))) | → | b(b(a(a(x1)))) | (1) |
b(b(b(a(x1)))) | → | b(b(a(a(x1)))) | (2) |
a(b(a(a(x1)))) | → | a(a(b(a(x1)))) | (3) |
b#(b(b(a(x1)))) | → | b#(a(a(x1))) | (4) |
a#(b(a(a(x1)))) | → | b#(a(x1)) | (5) |
b#(a(a(b(x1)))) | → | a#(a(x1)) | (6) |
b#(a(a(b(x1)))) | → | b#(b(a(a(x1)))) | (7) |
b#(a(a(b(x1)))) | → | a#(x1) | (8) |
a#(b(a(a(x1)))) | → | a#(b(a(x1))) | (9) |
b#(b(b(a(x1)))) | → | a#(a(x1)) | (10) |
b#(b(b(a(x1)))) | → | b#(b(a(a(x1)))) | (11) |
b#(a(a(b(x1)))) | → | b#(a(a(x1))) | (12) |
a#(b(a(a(x1)))) | → | a#(a(b(a(x1)))) | (13) |
The dependency pairs are split into 1 component.
a#(b(a(a(x1)))) | → | a#(a(b(a(x1)))) | (13) |
b#(a(a(b(x1)))) | → | b#(a(a(x1))) | (12) |
b#(b(b(a(x1)))) | → | b#(b(a(a(x1)))) | (11) |
b#(b(b(a(x1)))) | → | a#(a(x1)) | (10) |
b#(a(a(b(x1)))) | → | a#(a(x1)) | (6) |
a#(b(a(a(x1)))) | → | b#(a(x1)) | (5) |
a#(b(a(a(x1)))) | → | a#(b(a(x1))) | (9) |
b#(a(a(b(x1)))) | → | a#(x1) | (8) |
b#(a(a(b(x1)))) | → | b#(b(a(a(x1)))) | (7) |
b#(b(b(a(x1)))) | → | b#(a(a(x1))) | (4) |
[a(x1)] | = | x1 + 11798 |
[b(x1)] | = | x1 + 11799 |
[a#(x1)] | = | x1 + 23596 |
[b#(x1)] | = | x1 + 0 |
b(a(a(b(x1)))) | → | b(b(a(a(x1)))) | (1) |
a(b(a(a(x1)))) | → | a(a(b(a(x1)))) | (3) |
b(b(b(a(x1)))) | → | b(b(a(a(x1)))) | (2) |
b#(a(a(b(x1)))) | → | b#(a(a(x1))) | (12) |
b#(b(b(a(x1)))) | → | b#(b(a(a(x1)))) | (11) |
b#(b(b(a(x1)))) | → | a#(a(x1)) | (10) |
b#(a(a(b(x1)))) | → | a#(a(x1)) | (6) |
a#(b(a(a(x1)))) | → | b#(a(x1)) | (5) |
a#(b(a(a(x1)))) | → | a#(b(a(x1))) | (9) |
b#(a(a(b(x1)))) | → | a#(x1) | (8) |
b#(b(b(a(x1)))) | → | b#(a(a(x1))) | (4) |
The dependency pairs are split into 2 components.
b#(a(a(b(x1)))) | → | b#(b(a(a(x1)))) | (7) |
[a(x1)] | = | 2 |
[b(x1)] | = | 1 |
[a#(x1)] | = | x1 + 23596 |
[b#(x1)] | = | x1 + 0 |
b(a(a(b(x1)))) | → | b(b(a(a(x1)))) | (1) |
a(b(a(a(x1)))) | → | a(a(b(a(x1)))) | (3) |
b(b(b(a(x1)))) | → | b(b(a(a(x1)))) | (2) |
b#(a(a(b(x1)))) | → | b#(b(a(a(x1)))) | (7) |
The dependency pairs are split into 0 components.
a#(b(a(a(x1)))) | → | a#(a(b(a(x1)))) | (13) |
[a(x1)] | = | 1 |
[b(x1)] | = | 2 |
[a#(x1)] | = | x1 + 23596 |
[b#(x1)] | = | x1 + 0 |
b(a(a(b(x1)))) | → | b(b(a(a(x1)))) | (1) |
a(b(a(a(x1)))) | → | a(a(b(a(x1)))) | (3) |
b(b(b(a(x1)))) | → | b(b(a(a(x1)))) | (2) |
a#(b(a(a(x1)))) | → | a#(a(b(a(x1)))) | (13) |
The dependency pairs are split into 0 components.