The rewrite relation of the following TRS is considered.
b(a(a(b(x1)))) | → | b(b(b(a(x1)))) | (1) |
b(b(b(b(x1)))) | → | a(b(b(b(x1)))) | (2) |
b(a(b(b(x1)))) | → | b(a(b(a(x1)))) | (3) |
b#(a(b(b(x1)))) | → | b#(a(x1)) | (4) |
b#(a(a(b(x1)))) | → | b#(a(x1)) | (5) |
b#(a(a(b(x1)))) | → | b#(b(b(a(x1)))) | (6) |
b#(a(b(b(x1)))) | → | b#(a(b(a(x1)))) | (7) |
b#(a(a(b(x1)))) | → | b#(b(a(x1))) | (8) |
The dependency pairs are split into 1 component.
b#(a(a(b(x1)))) | → | b#(b(a(x1))) | (8) |
b#(a(b(b(x1)))) | → | b#(a(b(a(x1)))) | (7) |
b#(a(a(b(x1)))) | → | b#(b(b(a(x1)))) | (6) |
b#(a(a(b(x1)))) | → | b#(a(x1)) | (5) |
b#(a(b(b(x1)))) | → | b#(a(x1)) | (4) |
[a(x1)] | = | x1 + 2438 |
[b(x1)] | = | x1 + 2438 |
[b#(x1)] | = | x1 + 0 |
b(a(a(b(x1)))) | → | b(b(b(a(x1)))) | (1) |
b(a(b(b(x1)))) | → | b(a(b(a(x1)))) | (3) |
b(b(b(b(x1)))) | → | a(b(b(b(x1)))) | (2) |
b#(a(a(b(x1)))) | → | b#(b(a(x1))) | (8) |
b#(a(a(b(x1)))) | → | b#(a(x1)) | (5) |
b#(a(b(b(x1)))) | → | b#(a(x1)) | (4) |
The dependency pairs are split into 1 component.
b#(a(a(b(x1)))) | → | b#(b(b(a(x1)))) | (6) |
b#(a(b(b(x1)))) | → | b#(a(b(a(x1)))) | (7) |
[a(x1)] | = |
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[b(x1)] | = |
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[b#(x1)] | = |
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b(a(a(b(x1)))) | → | b(b(b(a(x1)))) | (1) |
b(a(b(b(x1)))) | → | b(a(b(a(x1)))) | (3) |
b(b(b(b(x1)))) | → | a(b(b(b(x1)))) | (2) |
b#(a(b(b(x1)))) | → | b#(a(b(a(x1)))) | (7) |
The dependency pairs are split into 1 component.
b#(a(a(b(x1)))) | → | b#(b(b(a(x1)))) | (6) |
[a(x1)] | = |
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[b(x1)] | = |
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[b#(x1)] | = |
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b(a(a(b(x1)))) | → | b(b(b(a(x1)))) | (1) |
b(a(b(b(x1)))) | → | b(a(b(a(x1)))) | (3) |
b(b(b(b(x1)))) | → | a(b(b(b(x1)))) | (2) |
b#(a(a(b(x1)))) | → | b#(b(b(a(x1)))) | (6) |
The dependency pairs are split into 0 components.