Certification Problem

Input (TPDB SRS_Standard/Zantema_04/z008)

The rewrite relation of the following TRS is considered.

a(s(x1)) s(a(x1)) (1)
b(a(b(s(x1)))) a(b(s(a(x1)))) (2)
b(a(b(b(x1)))) a(b(a(b(x1)))) (3)
a(b(a(a(x1)))) b(a(b(a(x1)))) (4)

Property / Task

Prove or disprove termination.

Answer / Result

Yes.

Proof (by NaTT @ termCOMP 2023)

1 Dependency Pair Transformation

The following set of initial dependency pairs has been identified.
b#(a(b(s(x1)))) b#(s(a(x1))) (5)
b#(a(b(b(x1)))) a#(b(x1)) (6)
a#(b(a(a(x1)))) a#(b(a(x1))) (7)
a#(s(x1)) a#(x1) (8)
a#(b(a(a(x1)))) b#(a(x1)) (9)
b#(a(b(b(x1)))) b#(a(b(x1))) (10)
b#(a(b(s(x1)))) a#(x1) (11)
b#(a(b(s(x1)))) a#(b(s(a(x1)))) (12)
a#(b(a(a(x1)))) b#(a(b(a(x1)))) (13)
b#(a(b(b(x1)))) a#(b(a(b(x1)))) (14)

1.1 Dependency Graph Processor

The dependency pairs are split into 1 component.