The rewrite relation of the following TRS is considered.
a(b(b(a(a(b(x1)))))) | → | a(a(b(b(a(b(a(x1))))))) | (1) |
a#(b(b(a(a(b(x1)))))) | → | a#(b(b(a(b(a(x1)))))) | (2) |
a#(b(b(a(a(b(x1)))))) | → | a#(b(a(x1))) | (3) |
a#(b(b(a(a(b(x1)))))) | → | a#(a(b(b(a(b(a(x1))))))) | (4) |
a#(b(b(a(a(b(x1)))))) | → | a#(x1) | (5) |
The dependency pairs are split into 1 component.
a#(b(b(a(a(b(x1)))))) | → | a#(x1) | (5) |
a#(b(b(a(a(b(x1)))))) | → | a#(a(b(b(a(b(a(x1))))))) | (4) |
a#(b(b(a(a(b(x1)))))) | → | a#(b(a(x1))) | (3) |
a#(b(b(a(a(b(x1)))))) | → | a#(b(b(a(b(a(x1)))))) | (2) |
[a(x1)] | = | x1 + 0 |
[b(x1)] | = | x1 + 28958 |
[a#(x1)] | = | x1 + 0 |
a(b(b(a(a(b(x1)))))) | → | a(a(b(b(a(b(a(x1))))))) | (1) |
a#(b(b(a(a(b(x1)))))) | → | a#(x1) | (5) |
a#(b(b(a(a(b(x1)))))) | → | a#(b(a(x1))) | (3) |
The dependency pairs are split into 1 component.
a#(b(b(a(a(b(x1)))))) | → | a#(b(b(a(b(a(x1)))))) | (2) |
a#(b(b(a(a(b(x1)))))) | → | a#(a(b(b(a(b(a(x1))))))) | (4) |
[a(x1)] | = | 0 |
[b(x1)] | = | x1 + 8856 |
[a#(x1)] | = | x1 + 0 |
a(b(b(a(a(b(x1)))))) | → | a(a(b(b(a(b(a(x1))))))) | (1) |
a#(b(b(a(a(b(x1)))))) | → | a#(a(b(b(a(b(a(x1))))))) | (4) |
The dependency pairs are split into 1 component.
a#(b(b(a(a(b(x1)))))) | → | a#(b(b(a(b(a(x1)))))) | (2) |
[a(x1)] | = |
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[b(x1)] | = |
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[a#(x1)] | = |
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a(b(b(a(a(b(x1)))))) | → | a(a(b(b(a(b(a(x1))))))) | (1) |
a#(b(b(a(a(b(x1)))))) | → | a#(b(b(a(b(a(x1)))))) | (2) |
The dependency pairs are split into 0 components.