The rewrite relation of the following TRS is considered.
b(c(a(x1))) | → | a(b(x1)) | (1) |
b(b(b(x1))) | → | c(a(c(x1))) | (2) |
c(d(x1)) | → | d(c(x1)) | (3) |
c(d(b(x1))) | → | d(c(c(x1))) | (4) |
d(c(x1)) | → | b(b(b(x1))) | (5) |
c(b(x1)) | → | d(a(x1)) | (6) |
d(b(c(x1))) | → | a(a(x1)) | (7) |
d(a(x1)) | → | b(x1) | (8) |
b#(b(b(x1))) | → | c#(x1) | (9) |
d#(c(x1)) | → | b#(x1) | (10) |
c#(d(b(x1))) | → | c#(x1) | (11) |
b#(c(a(x1))) | → | b#(x1) | (12) |
c#(d(b(x1))) | → | d#(c(c(x1))) | (13) |
c#(d(b(x1))) | → | c#(c(x1)) | (14) |
c#(d(x1)) | → | d#(c(x1)) | (15) |
d#(a(x1)) | → | b#(x1) | (16) |
d#(c(x1)) | → | b#(b(x1)) | (17) |
c#(b(x1)) | → | d#(a(x1)) | (18) |
b#(b(b(x1))) | → | c#(a(c(x1))) | (19) |
c#(d(x1)) | → | c#(x1) | (20) |
d#(c(x1)) | → | b#(b(b(x1))) | (21) |
The dependency pairs are split into 1 component.
d#(c(x1)) | → | b#(b(b(x1))) | (21) |
c#(d(b(x1))) | → | c#(c(x1)) | (14) |
c#(d(x1)) | → | c#(x1) | (20) |
c#(b(x1)) | → | d#(a(x1)) | (18) |
c#(d(b(x1))) | → | d#(c(c(x1))) | (13) |
b#(c(a(x1))) | → | b#(x1) | (12) |
c#(d(b(x1))) | → | c#(x1) | (11) |
d#(c(x1)) | → | b#(x1) | (10) |
d#(c(x1)) | → | b#(b(x1)) | (17) |
d#(a(x1)) | → | b#(x1) | (16) |
c#(d(x1)) | → | d#(c(x1)) | (15) |
b#(b(b(x1))) | → | c#(x1) | (9) |
[a(x1)] | = | x1 + 0 |
[d(x1)] | = | x1 + 61230 |
[b(x1)] | = | x1 + 30615 |
[c(x1)] | = | x1 + 30615 |
[d#(x1)] | = | x1 + 30617 |
[c#(x1)] | = | x1 + 4 |
[b#(x1)] | = | x1 + 0 |
c(d(b(x1))) | → | d(c(c(x1))) | (4) |
d(a(x1)) | → | b(x1) | (8) |
b(c(a(x1))) | → | a(b(x1)) | (1) |
c(d(x1)) | → | d(c(x1)) | (3) |
d(c(x1)) | → | b(b(b(x1))) | (5) |
d(b(c(x1))) | → | a(a(x1)) | (7) |
c(b(x1)) | → | d(a(x1)) | (6) |
b(b(b(x1))) | → | c(a(c(x1))) | (2) |
d#(c(x1)) | → | b#(b(b(x1))) | (21) |
c#(d(b(x1))) | → | c#(c(x1)) | (14) |
c#(d(x1)) | → | c#(x1) | (20) |
c#(b(x1)) | → | d#(a(x1)) | (18) |
c#(d(b(x1))) | → | d#(c(c(x1))) | (13) |
b#(c(a(x1))) | → | b#(x1) | (12) |
c#(d(b(x1))) | → | c#(x1) | (11) |
d#(c(x1)) | → | b#(x1) | (10) |
d#(c(x1)) | → | b#(b(x1)) | (17) |
d#(a(x1)) | → | b#(x1) | (16) |
c#(d(x1)) | → | d#(c(x1)) | (15) |
b#(b(b(x1))) | → | c#(x1) | (9) |
The dependency pairs are split into 0 components.