The rewrite relation of the following TRS is considered.
| a(p(x1)) | → | p(a(A(x1))) | (1) |
| a(A(x1)) | → | A(a(x1)) | (2) |
| p(A(A(x1))) | → | a(p(x1)) | (3) |
| p#(A(A(x1))) | → | a#(p(x1)) | (4) |
| a#(p(x1)) | → | a#(A(x1)) | (5) |
| p#(A(A(x1))) | → | p#(x1) | (6) |
| a#(A(x1)) | → | a#(x1) | (7) |
| a#(p(x1)) | → | p#(a(A(x1))) | (8) |
The dependency pairs are split into 1 component.
| a#(p(x1)) | → | p#(a(A(x1))) | (8) |
| a#(A(x1)) | → | a#(x1) | (7) |
| p#(A(A(x1))) | → | p#(x1) | (6) |
| a#(p(x1)) | → | a#(A(x1)) | (5) |
| p#(A(A(x1))) | → | a#(p(x1)) | (4) |
| [a(x1)] | = | x1 + 0 |
| [p#(x1)] | = | x1 + 1 |
| [p(x1)] | = | x1 + 1 |
| [A(x1)] | = | x1 + 0 |
| [a#(x1)] | = | x1 + 0 |
| a(p(x1)) | → | p(a(A(x1))) | (1) |
| p(A(A(x1))) | → | a(p(x1)) | (3) |
| a(A(x1)) | → | A(a(x1)) | (2) |
| a#(p(x1)) | → | a#(A(x1)) | (5) |
The dependency pairs are split into 1 component.
| a#(p(x1)) | → | p#(a(A(x1))) | (8) |
| p#(A(A(x1))) | → | p#(x1) | (6) |
| p#(A(A(x1))) | → | a#(p(x1)) | (4) |
| a#(A(x1)) | → | a#(x1) | (7) |
| [a(x1)] | = | x1 + 0 |
| [p#(x1)] | = | 1 |
| [p(x1)] | = | 1 |
| [A(x1)] | = | x1 + 32286 |
| [a#(x1)] | = | x1 + 0 |
| a(p(x1)) | → | p(a(A(x1))) | (1) |
| p(A(A(x1))) | → | a(p(x1)) | (3) |
| a(A(x1)) | → | A(a(x1)) | (2) |
| a#(A(x1)) | → | a#(x1) | (7) |
The dependency pairs are split into 1 component.
| a#(p(x1)) | → | p#(a(A(x1))) | (8) |
| p#(A(A(x1))) | → | p#(x1) | (6) |
| p#(A(A(x1))) | → | a#(p(x1)) | (4) |
| [a(x1)] | = |
x1 +
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| [p#(x1)] | = |
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| [p(x1)] | = |
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| [A(x1)] | = |
x1 +
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| [a#(x1)] | = |
x1 +
|
| a(p(x1)) | → | p(a(A(x1))) | (1) |
| p(A(A(x1))) | → | a(p(x1)) | (3) |
| a(A(x1)) | → | A(a(x1)) | (2) |
| a#(p(x1)) | → | p#(a(A(x1))) | (8) |
| p#(A(A(x1))) | → | p#(x1) | (6) |
| p#(A(A(x1))) | → | a#(p(x1)) | (4) |
The dependency pairs are split into 0 components.