Certification Problem

Input (TPDB SRS_Standard/ICFP_2010/63142)

The rewrite relation of the following TRS is considered.

0(0(0(1(0(2(0(2(1(2(0(2(2(x1))))))))))))) 0(0(1(0(1(1(0(2(1(0(0(0(1(0(1(1(0(x1))))))))))))))))) (1)
0(0(0(1(1(2(1(2(1(1(0(0(0(x1))))))))))))) 1(0(0(2(2(2(2(1(1(2(0(2(0(0(2(1(0(x1))))))))))))))))) (2)
0(1(0(1(0(0(1(0(0(2(1(2(0(x1))))))))))))) 0(1(0(2(0(0(2(1(0(0(0(0(0(1(0(0(0(x1))))))))))))))))) (3)
0(1(2(0(2(0(1(1(1(1(0(0(2(x1))))))))))))) 0(0(0(0(0(2(0(2(2(0(2(2(2(0(0(0(0(x1))))))))))))))))) (4)
0(1(2(1(1(0(0(2(2(1(0(2(2(x1))))))))))))) 1(0(0(2(1(0(0(2(0(0(0(2(0(2(2(2(2(x1))))))))))))))))) (5)
0(1(2(2(0(0(2(0(0(0(2(0(2(x1))))))))))))) 2(1(0(0(0(2(1(1(0(2(0(1(0(2(1(0(2(x1))))))))))))))))) (6)
0(2(0(1(0(1(1(0(1(2(0(0(1(x1))))))))))))) 0(1(1(0(0(0(2(1(1(1(0(2(0(0(2(0(1(x1))))))))))))))))) (7)
1(0(0(1(0(2(2(0(0(1(2(0(0(x1))))))))))))) 0(0(0(0(0(1(0(1(0(1(1(0(1(0(0(2(0(x1))))))))))))))))) (8)
1(0(1(1(1(2(2(2(2(1(0(0(0(x1))))))))))))) 2(1(0(0(1(0(1(0(2(2(1(1(0(0(2(2(2(x1))))))))))))))))) (9)
1(1(0(0(1(0(0(0(0(1(1(1(2(x1))))))))))))) 1(1(0(2(1(0(0(2(1(0(1(0(0(2(0(1(2(x1))))))))))))))))) (10)
1(1(2(0(1(0(2(1(2(0(1(0(2(x1))))))))))))) 1(1(2(1(0(1(0(2(1(1(1(0(1(0(2(0(2(x1))))))))))))))))) (11)
1(1(2(2(1(1(2(1(0(0(1(0(2(x1))))))))))))) 0(0(2(0(2(0(0(0(2(0(0(2(0(0(2(2(2(x1))))))))))))))))) (12)
2(0(0(0(1(1(2(1(0(2(2(0(0(x1))))))))))))) 1(1(0(2(0(1(0(2(2(1(1(1(0(2(2(0(0(x1))))))))))))))))) (13)
2(0(0(1(1(2(2(1(0(2(2(2(2(x1))))))))))))) 1(0(2(2(1(0(1(2(1(0(1(0(0(2(0(2(0(x1))))))))))))))))) (14)
2(0(0(2(1(2(1(1(0(1(0(0(2(x1))))))))))))) 2(1(1(1(1(0(2(0(1(0(1(0(2(1(0(0(2(x1))))))))))))))))) (15)
2(1(1(2(2(0(2(1(0(0(0(1(0(x1))))))))))))) 1(1(2(0(0(2(0(0(1(0(0(2(0(0(0(1(0(x1))))))))))))))))) (16)
2(1(2(1(1(2(1(0(0(1(0(1(0(x1))))))))))))) 2(2(1(1(1(0(0(0(0(1(0(0(2(2(0(1(0(x1))))))))))))))))) (17)
2(1(2(2(0(2(1(0(2(0(2(1(0(x1))))))))))))) 1(0(1(2(0(0(2(0(0(2(1(0(2(1(0(0(0(x1))))))))))))))))) (18)
2(2(0(1(1(1(1(0(1(0(1(2(0(x1))))))))))))) 0(1(1(0(1(1(0(0(2(2(0(1(1(0(1(0(0(x1))))))))))))))))) (19)

Property / Task

Prove or disprove termination.

Answer / Result

Yes.

Proof (by matchbox @ termCOMP 2023)

1 Closure Under Flat Contexts

Using the flat contexts

{2(), 1(), 0()}

We obtain the transformed TRS
2(0(0(0(1(0(2(0(2(1(2(0(2(2(x1)))))))))))))) 2(0(0(1(0(1(1(0(2(1(0(0(0(1(0(1(1(0(x1)))))))))))))))))) (20)
2(0(0(0(1(1(2(1(2(1(1(0(0(0(x1)))))))))))))) 2(1(0(0(2(2(2(2(1(1(2(0(2(0(0(2(1(0(x1)))))))))))))))))) (21)
2(0(1(0(1(0(0(1(0(0(2(1(2(0(x1)))))))))))))) 2(0(1(0(2(0(0(2(1(0(0(0(0(0(1(0(0(0(x1)))))))))))))))))) (22)
2(0(1(2(0(2(0(1(1(1(1(0(0(2(x1)))))))))))))) 2(0(0(0(0(0(2(0(2(2(0(2(2(2(0(0(0(0(x1)))))))))))))))))) (23)
2(0(1(2(1(1(0(0(2(2(1(0(2(2(x1)))))))))))))) 2(1(0(0(2(1(0(0(2(0(0(0(2(0(2(2(2(2(x1)))))))))))))))))) (24)
2(0(1(2(2(0(0(2(0(0(0(2(0(2(x1)))))))))))))) 2(2(1(0(0(0(2(1(1(0(2(0(1(0(2(1(0(2(x1)))))))))))))))))) (25)
2(0(2(0(1(0(1(1(0(1(2(0(0(1(x1)))))))))))))) 2(0(1(1(0(0(0(2(1(1(1(0(2(0(0(2(0(1(x1)))))))))))))))))) (26)
2(1(0(0(1(0(2(2(0(0(1(2(0(0(x1)))))))))))))) 2(0(0(0(0(0(1(0(1(0(1(1(0(1(0(0(2(0(x1)))))))))))))))))) (27)
2(1(0(1(1(1(2(2(2(2(1(0(0(0(x1)))))))))))))) 2(2(1(0(0(1(0(1(0(2(2(1(1(0(0(2(2(2(x1)))))))))))))))))) (28)
2(1(1(0(0(1(0(0(0(0(1(1(1(2(x1)))))))))))))) 2(1(1(0(2(1(0(0(2(1(0(1(0(0(2(0(1(2(x1)))))))))))))))))) (29)
2(1(1(2(0(1(0(2(1(2(0(1(0(2(x1)))))))))))))) 2(1(1(2(1(0(1(0(2(1(1(1(0(1(0(2(0(2(x1)))))))))))))))))) (30)
2(1(1(2(2(1(1(2(1(0(0(1(0(2(x1)))))))))))))) 2(0(0(2(0(2(0(0(0(2(0(0(2(0(0(2(2(2(x1)))))))))))))))))) (31)
2(2(0(0(0(1(1(2(1(0(2(2(0(0(x1)))))))))))))) 2(1(1(0(2(0(1(0(2(2(1(1(1(0(2(2(0(0(x1)))))))))))))))))) (32)
2(2(0(0(1(1(2(2(1(0(2(2(2(2(x1)))))))))))))) 2(1(0(2(2(1(0(1(2(1(0(1(0(0(2(0(2(0(x1)))))))))))))))))) (33)
2(2(0(0(2(1(2(1(1(0(1(0(0(2(x1)))))))))))))) 2(2(1(1(1(1(0(2(0(1(0(1(0(2(1(0(0(2(x1)))))))))))))))))) (34)
2(2(1(1(2(2(0(2(1(0(0(0(1(0(x1)))))))))))))) 2(1(1(2(0(0(2(0(0(1(0(0(2(0(0(0(1(0(x1)))))))))))))))))) (35)
2(2(1(2(1(1(2(1(0(0(1(0(1(0(x1)))))))))))))) 2(2(2(1(1(1(0(0(0(0(1(0(0(2(2(0(1(0(x1)))))))))))))))))) (36)
2(2(1(2(2(0(2(1(0(2(0(2(1(0(x1)))))))))))))) 2(1(0(1(2(0(0(2(0(0(2(1(0(2(1(0(0(0(x1)))))))))))))))))) (37)
2(2(2(0(1(1(1(1(0(1(0(1(2(0(x1)))))))))))))) 2(0(1(1(0(1(1(0(0(2(2(0(1(1(0(1(0(0(x1)))))))))))))))))) (38)
1(0(0(0(1(0(2(0(2(1(2(0(2(2(x1)))))))))))))) 1(0(0(1(0(1(1(0(2(1(0(0(0(1(0(1(1(0(x1)))))))))))))))))) (39)
1(0(0(0(1(1(2(1(2(1(1(0(0(0(x1)))))))))))))) 1(1(0(0(2(2(2(2(1(1(2(0(2(0(0(2(1(0(x1)))))))))))))))))) (40)
1(0(1(0(1(0(0(1(0(0(2(1(2(0(x1)))))))))))))) 1(0(1(0(2(0(0(2(1(0(0(0(0(0(1(0(0(0(x1)))))))))))))))))) (41)
1(0(1(2(0(2(0(1(1(1(1(0(0(2(x1)))))))))))))) 1(0(0(0(0(0(2(0(2(2(0(2(2(2(0(0(0(0(x1)))))))))))))))))) (42)
1(0(1(2(1(1(0(0(2(2(1(0(2(2(x1)))))))))))))) 1(1(0(0(2(1(0(0(2(0(0(0(2(0(2(2(2(2(x1)))))))))))))))))) (43)
1(0(1(2(2(0(0(2(0(0(0(2(0(2(x1)))))))))))))) 1(2(1(0(0(0(2(1(1(0(2(0(1(0(2(1(0(2(x1)))))))))))))))))) (44)
1(0(2(0(1(0(1(1(0(1(2(0(0(1(x1)))))))))))))) 1(0(1(1(0(0(0(2(1(1(1(0(2(0(0(2(0(1(x1)))))))))))))))))) (45)
1(1(0(0(1(0(2(2(0(0(1(2(0(0(x1)))))))))))))) 1(0(0(0(0(0(1(0(1(0(1(1(0(1(0(0(2(0(x1)))))))))))))))))) (46)
1(1(0(1(1(1(2(2(2(2(1(0(0(0(x1)))))))))))))) 1(2(1(0(0(1(0(1(0(2(2(1(1(0(0(2(2(2(x1)))))))))))))))))) (47)
1(1(1(0(0(1(0(0(0(0(1(1(1(2(x1)))))))))))))) 1(1(1(0(2(1(0(0(2(1(0(1(0(0(2(0(1(2(x1)))))))))))))))))) (48)
1(1(1(2(0(1(0(2(1(2(0(1(0(2(x1)))))))))))))) 1(1(1(2(1(0(1(0(2(1(1(1(0(1(0(2(0(2(x1)))))))))))))))))) (49)
1(1(1(2(2(1(1(2(1(0(0(1(0(2(x1)))))))))))))) 1(0(0(2(0(2(0(0(0(2(0(0(2(0(0(2(2(2(x1)))))))))))))))))) (50)
1(2(0(0(0(1(1(2(1(0(2(2(0(0(x1)))))))))))))) 1(1(1(0(2(0(1(0(2(2(1(1(1(0(2(2(0(0(x1)))))))))))))))))) (51)
1(2(0(0(1(1(2(2(1(0(2(2(2(2(x1)))))))))))))) 1(1(0(2(2(1(0(1(2(1(0(1(0(0(2(0(2(0(x1)))))))))))))))))) (52)
1(2(0(0(2(1(2(1(1(0(1(0(0(2(x1)))))))))))))) 1(2(1(1(1(1(0(2(0(1(0(1(0(2(1(0(0(2(x1)))))))))))))))))) (53)
1(2(1(1(2(2(0(2(1(0(0(0(1(0(x1)))))))))))))) 1(1(1(2(0(0(2(0(0(1(0(0(2(0(0(0(1(0(x1)))))))))))))))))) (54)
1(2(1(2(1(1(2(1(0(0(1(0(1(0(x1)))))))))))))) 1(2(2(1(1(1(0(0(0(0(1(0(0(2(2(0(1(0(x1)))))))))))))))))) (55)
1(2(1(2(2(0(2(1(0(2(0(2(1(0(x1)))))))))))))) 1(1(0(1(2(0(0(2(0(0(2(1(0(2(1(0(0(0(x1)))))))))))))))))) (56)
1(2(2(0(1(1(1(1(0(1(0(1(2(0(x1)))))))))))))) 1(0(1(1(0(1(1(0(0(2(2(0(1(1(0(1(0(0(x1)))))))))))))))))) (57)
0(0(0(0(1(0(2(0(2(1(2(0(2(2(x1)))))))))))))) 0(0(0(1(0(1(1(0(2(1(0(0(0(1(0(1(1(0(x1)))))))))))))))))) (58)
0(0(0(0(1(1(2(1(2(1(1(0(0(0(x1)))))))))))))) 0(1(0(0(2(2(2(2(1(1(2(0(2(0(0(2(1(0(x1)))))))))))))))))) (59)
0(0(1(0(1(0(0(1(0(0(2(1(2(0(x1)))))))))))))) 0(0(1(0(2(0(0(2(1(0(0(0(0(0(1(0(0(0(x1)))))))))))))))))) (60)
0(0(1(2(0(2(0(1(1(1(1(0(0(2(x1)))))))))))))) 0(0(0(0(0(0(2(0(2(2(0(2(2(2(0(0(0(0(x1)))))))))))))))))) (61)
0(0(1(2(1(1(0(0(2(2(1(0(2(2(x1)))))))))))))) 0(1(0(0(2(1(0(0(2(0(0(0(2(0(2(2(2(2(x1)))))))))))))))))) (62)
0(0(1(2(2(0(0(2(0(0(0(2(0(2(x1)))))))))))))) 0(2(1(0(0(0(2(1(1(0(2(0(1(0(2(1(0(2(x1)))))))))))))))))) (63)
0(0(2(0(1(0(1(1(0(1(2(0(0(1(x1)))))))))))))) 0(0(1(1(0(0(0(2(1(1(1(0(2(0(0(2(0(1(x1)))))))))))))))))) (64)
0(1(0(0(1(0(2(2(0(0(1(2(0(0(x1)))))))))))))) 0(0(0(0(0(0(1(0(1(0(1(1(0(1(0(0(2(0(x1)))))))))))))))))) (65)
0(1(0(1(1(1(2(2(2(2(1(0(0(0(x1)))))))))))))) 0(2(1(0(0(1(0(1(0(2(2(1(1(0(0(2(2(2(x1)))))))))))))))))) (66)
0(1(1(0(0(1(0(0(0(0(1(1(1(2(x1)))))))))))))) 0(1(1(0(2(1(0(0(2(1(0(1(0(0(2(0(1(2(x1)))))))))))))))))) (67)
0(1(1(2(0(1(0(2(1(2(0(1(0(2(x1)))))))))))))) 0(1(1(2(1(0(1(0(2(1(1(1(0(1(0(2(0(2(x1)))))))))))))))))) (68)
0(1(1(2(2(1(1(2(1(0(0(1(0(2(x1)))))))))))))) 0(0(0(2(0(2(0(0(0(2(0(0(2(0(0(2(2(2(x1)))))))))))))))))) (69)
0(2(0(0(0(1(1(2(1(0(2(2(0(0(x1)))))))))))))) 0(1(1(0(2(0(1(0(2(2(1(1(1(0(2(2(0(0(x1)))))))))))))))))) (70)
0(2(0(0(1(1(2(2(1(0(2(2(2(2(x1)))))))))))))) 0(1(0(2(2(1(0(1(2(1(0(1(0(0(2(0(2(0(x1)))))))))))))))))) (71)
0(2(0(0(2(1(2(1(1(0(1(0(0(2(x1)))))))))))))) 0(2(1(1(1(1(0(2(0(1(0(1(0(2(1(0(0(2(x1)))))))))))))))))) (72)
0(2(1(1(2(2(0(2(1(0(0(0(1(0(x1)))))))))))))) 0(1(1(2(0(0(2(0(0(1(0(0(2(0(0(0(1(0(x1)))))))))))))))))) (73)
0(2(1(2(1(1(2(1(0(0(1(0(1(0(x1)))))))))))))) 0(2(2(1(1(1(0(0(0(0(1(0(0(2(2(0(1(0(x1)))))))))))))))))) (74)
0(2(1(2(2(0(2(1(0(2(0(2(1(0(x1)))))))))))))) 0(1(0(1(2(0(0(2(0(0(2(1(0(2(1(0(0(0(x1)))))))))))))))))) (75)
0(2(2(0(1(1(1(1(0(1(0(1(2(0(x1)))))))))))))) 0(0(1(1(0(1(1(0(0(2(2(0(1(1(0(1(0(0(x1)))))))))))))))))) (76)

1.1 Semantic Labeling

The following interpretations form a model of the rules.

As carrier we take the set {0,1,2}. Symbols are labeled by the interpretation of their arguments using the interpretations (modulo 3):

[2(x1)] = 3x1 + 0
[1(x1)] = 3x1 + 1
[0(x1)] = 3x1 + 2

We obtain the labeled TRS

There are 171 ruless (increase limit for explicit display).

1.1.1 Rule Removal

Using the matrix interpretations of dimension 1 with strict dimension 1 over the rationals with delta = 1
[20(x1)] = x1 +
6
[21(x1)] = x1 +
0
[22(x1)] = x1 +
1
[10(x1)] = x1 +
22
[11(x1)] = x1 +
5
[12(x1)] = x1 +
0
[00(x1)] = x1 +
0
[01(x1)] = x1 +
0
[02(x1)] = x1 +
1
all of the following rules can be deleted.

There are 171 ruless (increase limit for explicit display).

1.1.1.1 R is empty

There are no rules in the TRS. Hence, it is terminating.