The rewrite relation of the following TRS is considered.
0(1(1(2(x1)))) |
→ |
3(4(4(2(x1)))) |
(1) |
2(1(0(2(5(5(x1)))))) |
→ |
4(0(5(2(5(x1))))) |
(2) |
4(2(0(3(1(2(x1)))))) |
→ |
5(5(0(5(2(5(x1)))))) |
(3) |
0(1(5(0(4(4(5(x1))))))) |
→ |
3(0(0(4(5(0(x1)))))) |
(4) |
0(4(1(2(2(4(5(x1))))))) |
→ |
0(0(1(5(4(5(x1)))))) |
(5) |
3(5(4(0(0(4(0(x1))))))) |
→ |
0(0(0(5(4(0(x1)))))) |
(6) |
2(3(4(3(1(0(2(4(x1)))))))) |
→ |
0(4(5(3(1(4(x1)))))) |
(7) |
2(5(2(4(4(3(1(0(0(x1))))))))) |
→ |
4(2(5(5(4(5(5(0(x1)))))))) |
(8) |
5(4(1(5(5(5(3(3(0(x1))))))))) |
→ |
5(3(5(0(4(3(5(4(0(x1))))))))) |
(9) |
4(0(5(1(2(1(3(3(0(5(3(x1))))))))))) |
→ |
1(2(1(4(4(3(2(5(0(2(3(x1))))))))))) |
(10) |
4(5(2(5(0(0(2(2(0(4(1(x1))))))))))) |
→ |
4(4(4(3(3(1(3(5(5(1(1(x1))))))))))) |
(11) |
1(2(3(1(4(1(3(2(0(5(1(4(x1)))))))))))) |
→ |
1(0(4(4(5(1(2(4(3(3(0(1(x1)))))))))))) |
(12) |
1(1(5(1(4(3(4(1(1(5(1(2(5(x1))))))))))))) |
→ |
5(0(0(3(3(0(5(5(5(4(2(3(x1)))))))))))) |
(13) |
1(4(0(0(1(3(4(3(3(0(3(0(4(5(x1)))))))))))))) |
→ |
5(5(3(3(5(0(4(5(4(1(5(0(0(x1))))))))))))) |
(14) |
2(1(0(3(2(0(2(0(3(3(2(3(4(0(5(x1))))))))))))))) |
→ |
2(2(3(3(5(5(5(3(1(4(0(5(0(2(2(x1))))))))))))))) |
(15) |
0(5(5(4(0(5(3(1(5(4(4(2(2(5(3(4(x1)))))))))))))))) |
→ |
0(4(2(1(2(0(2(2(4(3(3(2(2(4(4(3(3(4(x1)))))))))))))))))) |
(16) |
2(4(4(5(0(1(5(0(3(5(1(1(5(2(0(4(4(x1))))))))))))))))) |
→ |
2(5(2(4(3(5(4(2(4(3(4(1(3(4(5(5(4(1(2(4(x1)))))))))))))))))))) |
(17) |
1(2(2(2(5(0(0(3(3(5(2(4(5(1(1(0(4(3(x1)))))))))))))))))) |
→ |
1(1(3(0(0(0(3(1(5(1(0(2(3(0(0(x1))))))))))))))) |
(18) |
0(2(1(4(1(2(5(0(0(1(3(1(5(5(5(5(1(3(4(x1))))))))))))))))))) |
→ |
3(5(5(1(3(2(2(2(5(2(5(5(5(2(0(4(1(1(4(4(x1)))))))))))))))))))) |
(19) |
1(3(1(0(2(2(4(4(1(3(4(2(0(5(2(1(3(5(4(x1))))))))))))))))))) |
→ |
1(4(2(0(2(0(5(5(2(2(0(5(4(3(4(4(4(x1))))))))))))))))) |
(20) |
1(3(2(0(0(1(1(5(5(3(1(3(0(2(3(4(5(5(5(x1))))))))))))))))))) |
→ |
3(0(0(5(2(5(2(2(1(4(2(2(0(0(2(5(5(3(0(2(x1)))))))))))))))))))) |
(21) |
2(2(2(5(1(3(5(5(0(4(0(4(5(1(1(2(0(2(5(x1))))))))))))))))))) |
→ |
3(2(4(4(2(3(3(1(1(2(0(3(3(1(1(4(5(x1))))))))))))))))) |
(22) |
2(5(3(4(5(1(1(5(5(1(2(1(3(3(3(5(4(5(1(x1))))))))))))))))))) |
→ |
5(4(5(4(5(1(1(0(4(2(5(4(1(2(0(1(3(1(x1)))))))))))))))))) |
(23) |
3(2(1(3(3(5(5(5(4(2(4(4(5(1(5(1(3(0(4(x1))))))))))))))))))) |
→ |
0(4(4(3(0(1(1(3(0(4(2(2(3(3(0(4(0(1(x1)))))))))))))))))) |
(24) |
2(5(5(2(2(0(1(2(0(3(3(5(1(3(2(2(0(2(3(4(3(x1))))))))))))))))))))) |
→ |
4(4(0(4(1(1(4(5(2(5(1(0(1(4(4(1(1(3(3(x1))))))))))))))))))) |
(25) |
There are 150 ruless (increase limit for explicit display).
As carrier we take the set
{0,...,5}.
Symbols are labeled by the interpretation of their arguments using the interpretations
(modulo 6):
There are 900 ruless (increase limit for explicit display).
There are 900 ruless (increase limit for explicit display).
There are no rules in the TRS. Hence, it is terminating.