The rewrite relation of the following TRS is considered.
a(x1) | → | x1 | (1) |
a(b(b(a(x1)))) | → | a(c(c(b(x1)))) | (2) |
c(x1) | → | a(b(x1)) | (3) |
c#(x1) | → | a#(b(x1)) | (4) |
a#(b(b(a(x1)))) | → | c#(c(b(x1))) | (5) |
a#(b(b(a(x1)))) | → | c#(b(x1)) | (6) |
a#(b(b(a(x1)))) | → | a#(c(c(b(x1)))) | (7) |
The dependency pairs are split into 1 component.
c#(x1) | → | a#(b(x1)) | (4) |
a#(b(b(a(x1)))) | → | c#(c(b(x1))) | (5) |
a#(b(b(a(x1)))) | → | c#(b(x1)) | (6) |
a#(b(b(a(x1)))) | → | a#(c(c(b(x1)))) | (7) |
[c(x1)] | = |
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[b(x1)] | = |
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[a(x1)] | = |
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[c#(x1)] | = |
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[a#(x1)] | = |
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a(x1) | → | x1 | (1) |
a(b(b(a(x1)))) | → | a(c(c(b(x1)))) | (2) |
c(x1) | → | a(b(x1)) | (3) |
a#(b(b(a(x1)))) | → | c#(c(b(x1))) | (5) |
a#(b(b(a(x1)))) | → | c#(b(x1)) | (6) |
a#(b(b(a(x1)))) | → | a#(c(c(b(x1)))) | (7) |
[c(x1)] | = |
x1 +
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[b(x1)] | = |
x1 +
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[a(x1)] | = |
x1 +
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[c#(x1)] | = |
x1 +
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[a#(x1)] | = |
x1 +
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a(x1) | → | x1 | (1) |
a(b(b(a(x1)))) | → | a(c(c(b(x1)))) | (2) |
c(x1) | → | a(b(x1)) | (3) |
c#(x1) | → | a#(b(x1)) | (4) |
The dependency pairs are split into 0 components.