The rewrite relation of the following TRS is considered.
a#(a(b(a(a(b(a(b(a(a(b(x1))))))))))) |
→ |
a#(x1) |
(2) |
a#(a(b(a(a(b(a(b(a(a(b(x1))))))))))) |
→ |
a#(b(a(x1))) |
(3) |
a#(a(b(a(a(b(a(b(a(a(b(x1))))))))))) |
→ |
a#(b(a(b(a(a(b(a(x1)))))))) |
(4) |
a#(a(b(a(a(b(a(b(a(a(b(x1))))))))))) |
→ |
a#(b(a(b(a(a(b(a(b(a(a(b(a(x1))))))))))))) |
(5) |
a#(a(b(a(a(b(a(b(a(a(b(x1))))))))))) |
→ |
a#(b(a(a(b(a(x1)))))) |
(6) |
a#(a(b(a(a(b(a(b(a(a(b(x1))))))))))) |
→ |
a#(b(a(a(b(a(b(a(a(b(a(x1))))))))))) |
(7) |
a#(a(b(a(a(b(a(b(a(a(b(x1))))))))))) |
→ |
a#(a(b(a(x1)))) |
(8) |
a#(a(b(a(a(b(a(b(a(a(b(x1))))))))))) |
→ |
a#(a(b(a(b(a(a(b(a(x1))))))))) |
(9) |
a#(a(b(a(a(b(a(b(a(a(b(x1))))))))))) |
→ |
a#(a(b(a(b(a(a(b(a(b(a(a(b(a(x1)))))))))))))) |
(10) |
The dependency pairs are split into 1
component.