The rewrite relation of the following TRS is considered.
a(a(b(a(a(b(a(b(a(a(b(x1))))))))))) | → | a(a(b(a(b(a(a(b(a(b(a(a(b(a(x1)))))))))))))) | (1) |
a#(a(b(a(a(b(a(b(a(a(b(x1))))))))))) | → | a#(x1) | (2) |
a#(a(b(a(a(b(a(b(a(a(b(x1))))))))))) | → | a#(b(a(x1))) | (3) |
a#(a(b(a(a(b(a(b(a(a(b(x1))))))))))) | → | a#(b(a(b(a(a(b(a(x1)))))))) | (4) |
a#(a(b(a(a(b(a(b(a(a(b(x1))))))))))) | → | a#(b(a(b(a(a(b(a(b(a(a(b(a(x1))))))))))))) | (5) |
a#(a(b(a(a(b(a(b(a(a(b(x1))))))))))) | → | a#(b(a(a(b(a(x1)))))) | (6) |
a#(a(b(a(a(b(a(b(a(a(b(x1))))))))))) | → | a#(b(a(a(b(a(b(a(a(b(a(x1))))))))))) | (7) |
a#(a(b(a(a(b(a(b(a(a(b(x1))))))))))) | → | a#(a(b(a(x1)))) | (8) |
a#(a(b(a(a(b(a(b(a(a(b(x1))))))))))) | → | a#(a(b(a(b(a(a(b(a(x1))))))))) | (9) |
a#(a(b(a(a(b(a(b(a(a(b(x1))))))))))) | → | a#(a(b(a(b(a(a(b(a(b(a(a(b(a(x1)))))))))))))) | (10) |
The dependency pairs are split into 1 component.
a#(a(b(a(a(b(a(b(a(a(b(x1))))))))))) | → | a#(x1) | (2) |
a#(a(b(a(a(b(a(b(a(a(b(x1))))))))))) | → | a#(a(b(a(x1)))) | (8) |
[b(x1)] | = |
|
||||||||||||||||||||||||||
[a(x1)] | = |
|
||||||||||||||||||||||||||
[a#(x1)] | = |
|
a(a(b(a(a(b(a(b(a(a(b(x1))))))))))) | → | a(a(b(a(b(a(a(b(a(b(a(a(b(a(x1)))))))))))))) | (1) |
a#(a(b(a(a(b(a(b(a(a(b(x1))))))))))) | → | a#(x1) | (2) |
a#(a(b(a(a(b(a(b(a(a(b(x1))))))))))) | → | a#(a(b(a(x1)))) | (8) |
The dependency pairs are split into 0 components.