The rewrite relation of the following TRS is considered.
| b(a(a(b(b(a(a(b(x1)))))))) | → | a(a(b(b(a(a(b(a(a(b(b(x1))))))))))) | (1) |
| b(a(a(b(b(a(a(b(x1)))))))) | → | b(b(a(a(b(a(a(b(b(a(a(x1))))))))))) | (2) |
| b#(a(a(b(b(a(a(b(x1)))))))) | → | b#(b(a(a(x1)))) | (3) |
| b#(a(a(b(b(a(a(b(x1)))))))) | → | b#(b(a(a(b(a(a(b(b(a(a(x1))))))))))) | (4) |
| b#(a(a(b(b(a(a(b(x1)))))))) | → | b#(a(a(x1))) | (5) |
| b#(a(a(b(b(a(a(b(x1)))))))) | → | b#(a(a(b(b(a(a(x1))))))) | (6) |
| b#(a(a(b(b(a(a(b(x1)))))))) | → | b#(a(a(b(a(a(b(b(a(a(x1)))))))))) | (7) |
The dependency pairs are split into 1 component.
| b#(a(a(b(b(a(a(b(x1)))))))) | → | b#(b(a(a(x1)))) | (3) |
| b#(a(a(b(b(a(a(b(x1)))))))) | → | b#(b(a(a(b(a(a(b(b(a(a(x1))))))))))) | (4) |
| b#(a(a(b(b(a(a(b(x1)))))))) | → | b#(a(a(x1))) | (5) |
| b#(a(a(b(b(a(a(b(x1)))))))) | → | b#(a(a(b(b(a(a(x1))))))) | (6) |
| b#(a(a(b(b(a(a(b(x1)))))))) | → | b#(a(a(b(a(a(b(b(a(a(x1)))))))))) | (7) |
| [b(x1)] | = |
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| [a(x1)] | = |
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| [b#(x1)] | = |
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| b(a(a(b(b(a(a(b(x1)))))))) | → | b(b(a(a(b(a(a(b(b(a(a(x1))))))))))) | (2) |
| b#(a(a(b(b(a(a(b(x1)))))))) | → | b#(b(a(a(x1)))) | (3) |
| b#(a(a(b(b(a(a(b(x1)))))))) | → | b#(b(a(a(b(a(a(b(b(a(a(x1))))))))))) | (4) |
The dependency pairs are split into 1 component.
| b#(a(a(b(b(a(a(b(x1)))))))) | → | b#(a(a(x1))) | (5) |
| b#(a(a(b(b(a(a(b(x1)))))))) | → | b#(a(a(b(b(a(a(x1))))))) | (6) |
| b#(a(a(b(b(a(a(b(x1)))))))) | → | b#(a(a(b(a(a(b(b(a(a(x1)))))))))) | (7) |
| [b(x1)] | = |
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| [a(x1)] | = |
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| [b#(x1)] | = |
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| b(a(a(b(b(a(a(b(x1)))))))) | → | b(b(a(a(b(a(a(b(b(a(a(x1))))))))))) | (2) |
| b#(a(a(b(b(a(a(b(x1)))))))) | → | b#(a(a(x1))) | (5) |
| b#(a(a(b(b(a(a(b(x1)))))))) | → | b#(a(a(b(b(a(a(x1))))))) | (6) |
| b#(a(a(b(b(a(a(b(x1)))))))) | → | b#(a(a(b(a(a(b(b(a(a(x1)))))))))) | (7) |
The dependency pairs are split into 0 components.