The rewrite relation of the following TRS is considered.
| c(a(a(b(c(c(a(a(b(c(x1)))))))))) | → | a(a(b(c(c(a(a(b(c(a(a(b(c(c(x1)))))))))))))) | (1) |
| c#(a(a(b(c(c(a(a(b(c(x1)))))))))) | → | c#(c(x1)) | (2) |
| c#(a(a(b(c(c(a(a(b(c(x1)))))))))) | → | c#(c(a(a(b(c(a(a(b(c(c(x1))))))))))) | (3) |
| c#(a(a(b(c(c(a(a(b(c(x1)))))))))) | → | c#(a(a(b(c(c(x1)))))) | (4) |
| c#(a(a(b(c(c(a(a(b(c(x1)))))))))) | → | c#(a(a(b(c(a(a(b(c(c(x1)))))))))) | (5) |
The dependency pairs are split into 1 component.
| c#(a(a(b(c(c(a(a(b(c(x1)))))))))) | → | c#(c(x1)) | (2) |
| c#(a(a(b(c(c(a(a(b(c(x1)))))))))) | → | c#(c(a(a(b(c(a(a(b(c(c(x1))))))))))) | (3) |
| c#(a(a(b(c(c(a(a(b(c(x1)))))))))) | → | c#(a(a(b(c(c(x1)))))) | (4) |
| c#(a(a(b(c(c(a(a(b(c(x1)))))))))) | → | c#(a(a(b(c(a(a(b(c(c(x1)))))))))) | (5) |
| [c(x1)] | = |
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| [b(x1)] | = |
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| [a(x1)] | = |
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| [c#(x1)] | = |
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| c(a(a(b(c(c(a(a(b(c(x1)))))))))) | → | a(a(b(c(c(a(a(b(c(a(a(b(c(c(x1)))))))))))))) | (1) |
| c#(a(a(b(c(c(a(a(b(c(x1)))))))))) | → | c#(a(a(b(c(a(a(b(c(c(x1)))))))))) | (5) |
The dependency pairs are split into 1 component.
| c#(a(a(b(c(c(a(a(b(c(x1)))))))))) | → | c#(c(x1)) | (2) |
| c#(a(a(b(c(c(a(a(b(c(x1)))))))))) | → | c#(c(a(a(b(c(a(a(b(c(c(x1))))))))))) | (3) |
| c#(a(a(b(c(c(a(a(b(c(x1)))))))))) | → | c#(a(a(b(c(c(x1)))))) | (4) |
| [c(x1)] | = |
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| [b(x1)] | = |
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| [a(x1)] | = |
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| [c#(x1)] | = |
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| c(a(a(b(c(c(a(a(b(c(x1)))))))))) | → | a(a(b(c(c(a(a(b(c(a(a(b(c(c(x1)))))))))))))) | (1) |
| c#(a(a(b(c(c(a(a(b(c(x1)))))))))) | → | c#(c(a(a(b(c(a(a(b(c(c(x1))))))))))) | (3) |
The dependency pairs are split into 1 component.
| c#(a(a(b(c(c(a(a(b(c(x1)))))))))) | → | c#(c(x1)) | (2) |
| c#(a(a(b(c(c(a(a(b(c(x1)))))))))) | → | c#(a(a(b(c(c(x1)))))) | (4) |
| [c(x1)] | = |
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| [b(x1)] | = |
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| [a(x1)] | = |
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| [c#(x1)] | = |
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| c(a(a(b(c(c(a(a(b(c(x1)))))))))) | → | a(a(b(c(c(a(a(b(c(a(a(b(c(c(x1)))))))))))))) | (1) |
| c#(a(a(b(c(c(a(a(b(c(x1)))))))))) | → | c#(c(x1)) | (2) |
| c#(a(a(b(c(c(a(a(b(c(x1)))))))))) | → | c#(a(a(b(c(c(x1)))))) | (4) |
The dependency pairs are split into 0 components.