Certification Problem
Input (TPDB SRS_Standard/Zantema_04/z003)
The rewrite relation of the following TRS is considered.
b(c(a(x1))) |
→ |
a(b(a(b(c(x1))))) |
(1) |
b(x1) |
→ |
c(c(x1)) |
(2) |
c(d(x1)) |
→ |
a(b(c(a(x1)))) |
(3) |
a(a(x1)) |
→ |
a(c(b(a(x1)))) |
(4) |
Property / Task
Prove or disprove termination.Answer / Result
Yes.Proof (by matchbox @ termCOMP 2023)
1 Rule Removal
Using the
matrix interpretations of dimension 1 with strict dimension 1 over the rationals with delta = 1
[d(x1)] |
= |
x1 +
|
[c(x1)] |
= |
x1 +
|
[b(x1)] |
= |
x1 +
|
[a(x1)] |
= |
x1 +
|
all of the following rules can be deleted.
c(d(x1)) |
→ |
a(b(c(a(x1)))) |
(3) |
1.1 Dependency Pair Transformation
The following set of initial dependency pairs has been identified.
b#(c(a(x1))) |
→ |
b#(c(x1)) |
(5) |
b#(c(a(x1))) |
→ |
b#(a(b(c(x1)))) |
(6) |
b#(c(a(x1))) |
→ |
a#(b(c(x1))) |
(7) |
b#(c(a(x1))) |
→ |
a#(b(a(b(c(x1))))) |
(8) |
a#(a(x1)) |
→ |
b#(a(x1)) |
(9) |
a#(a(x1)) |
→ |
a#(c(b(a(x1)))) |
(10) |
1.1.1 Dependency Graph Processor
The dependency pairs are split into 1
component.