The rewrite relation of the following TRS is considered.
a(b(a(a(b(x1))))) | → | c(c(c(c(a(x1))))) | (1) |
c(x1) | → | b(a(a(b(x1)))) | (2) |
b(a(a(b(a(x1))))) | → | a(c(c(c(c(x1))))) | (3) |
c(x1) | → | b(a(a(b(x1)))) | (2) |
c#(x1) | → | b#(x1) | (4) |
c#(x1) | → | b#(a(a(b(x1)))) | (5) |
b#(a(a(b(a(x1))))) | → | c#(x1) | (6) |
b#(a(a(b(a(x1))))) | → | c#(c(x1)) | (7) |
b#(a(a(b(a(x1))))) | → | c#(c(c(x1))) | (8) |
b#(a(a(b(a(x1))))) | → | c#(c(c(c(x1)))) | (9) |
The dependency pairs are split into 1 component.
c#(x1) | → | b#(x1) | (4) |
b#(a(a(b(a(x1))))) | → | c#(x1) | (6) |
c#(x1) | → | b#(a(a(b(x1)))) | (5) |
b#(a(a(b(a(x1))))) | → | c#(c(x1)) | (7) |
b#(a(a(b(a(x1))))) | → | c#(c(c(x1))) | (8) |
b#(a(a(b(a(x1))))) | → | c#(c(c(c(x1)))) | (9) |
[c(x1)] | = |
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[b(x1)] | = |
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[a(x1)] | = |
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[c#(x1)] | = |
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[b#(x1)] | = |
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b(a(a(b(a(x1))))) | → | a(c(c(c(c(x1))))) | (3) |
c(x1) | → | b(a(a(b(x1)))) | (2) |
b#(a(a(b(a(x1))))) | → | c#(x1) | (6) |
b#(a(a(b(a(x1))))) | → | c#(c(x1)) | (7) |
b#(a(a(b(a(x1))))) | → | c#(c(c(x1))) | (8) |
b#(a(a(b(a(x1))))) | → | c#(c(c(c(x1)))) | (9) |
[c(x1)] | = |
x1 +
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[b(x1)] | = |
x1 +
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[a(x1)] | = |
x1 +
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[c#(x1)] | = |
x1 +
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[b#(x1)] | = |
x1 +
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b(a(a(b(a(x1))))) | → | a(c(c(c(c(x1))))) | (3) |
c(x1) | → | b(a(a(b(x1)))) | (2) |
c#(x1) | → | b#(x1) | (4) |
c#(x1) | → | b#(a(a(b(x1)))) | (5) |
The dependency pairs are split into 0 components.