Certification Problem

Input (TPDB SRS_Standard/ICFP_2010/214183)

The rewrite relation of the following TRS is considered.

0(0(1(2(x1)))) 2(3(1(0(0(x1))))) (1)
0(0(1(2(x1)))) 3(1(0(0(2(x1))))) (2)
0(0(1(2(x1)))) 0(0(2(3(1(1(x1)))))) (3)
0(1(0(4(x1)))) 3(1(4(0(0(x1))))) (4)
0(1(0(4(x1)))) 3(4(0(0(3(1(x1)))))) (5)
0(1(0(4(x1)))) 4(3(1(0(5(0(x1)))))) (6)
0(1(0(4(x1)))) 5(0(4(3(1(0(x1)))))) (7)
0(1(0(5(x1)))) 3(5(3(1(0(0(x1)))))) (8)
0(1(0(5(x1)))) 5(3(1(0(0(2(x1)))))) (9)
0(1(4(2(x1)))) 2(3(1(4(0(x1))))) (10)
0(1(4(2(x1)))) 4(0(3(1(2(4(x1)))))) (11)
0(1(4(2(x1)))) 4(3(1(1(0(2(x1)))))) (12)
0(5(0(4(x1)))) 4(0(0(3(5(x1))))) (13)
0(5(0(4(x1)))) 5(0(0(3(4(x1))))) (14)
0(5(0(5(x1)))) 3(5(2(0(0(5(x1)))))) (15)
0(5(0(5(x1)))) 5(3(5(4(0(0(x1)))))) (16)
0(5(0(5(x1)))) 5(5(3(4(0(0(x1)))))) (17)
2(0(1(2(x1)))) 0(2(4(1(2(x1))))) (18)
2(0(1(2(x1)))) 2(5(0(2(2(1(x1)))))) (19)
2(0(1(2(x1)))) 3(1(3(2(2(0(x1)))))) (20)
2(0(4(2(x1)))) 4(0(2(2(1(x1))))) (21)
2(0(4(2(x1)))) 4(0(2(1(2(1(x1)))))) (22)
2(0(5(2(x1)))) 0(2(1(5(2(2(x1)))))) (23)
3(0(4(2(x1)))) 0(3(4(1(1(2(x1)))))) (24)
3(0(4(2(x1)))) 4(3(3(1(0(2(x1)))))) (25)
0(0(1(2(2(x1))))) 0(0(2(1(2(1(x1)))))) (26)
0(0(1(3(2(x1))))) 0(3(1(2(0(4(x1)))))) (27)
0(0(1(3(2(x1))))) 2(5(0(3(1(0(x1)))))) (28)
0(0(5(2(2(x1))))) 0(0(2(5(2(1(x1)))))) (29)
0(1(0(5(2(x1))))) 0(2(1(0(3(5(x1)))))) (30)
0(1(0(5(5(x1))))) 1(3(5(0(0(5(x1)))))) (31)
0(1(2(0(5(x1))))) 4(0(5(2(1(0(x1)))))) (32)
0(1(3(0(4(x1))))) 1(0(3(4(4(0(x1)))))) (33)
0(1(3(4(2(x1))))) 4(2(1(0(3(4(x1)))))) (34)
0(1(4(2(2(x1))))) 1(1(0(2(4(2(x1)))))) (35)
0(1(4(2(4(x1))))) 4(0(2(3(1(4(x1)))))) (36)
0(1(4(3(2(x1))))) 3(1(2(0(4(4(x1)))))) (37)
0(3(0(0(5(x1))))) 5(3(1(0(0(0(x1)))))) (38)
0(4(1(0(4(x1))))) 4(0(2(1(4(0(x1)))))) (39)
0(4(3(2(2(x1))))) 4(2(0(3(5(2(x1)))))) (40)
0(5(1(0(4(x1))))) 5(2(4(1(0(0(x1)))))) (41)
0(5(1(4(2(x1))))) 4(0(3(5(1(2(x1)))))) (42)
2(1(0(1(2(x1))))) 2(1(1(0(2(3(x1)))))) (43)
2(4(0(5(2(x1))))) 0(4(2(3(5(2(x1)))))) (44)
3(0(0(1(2(x1))))) 0(3(5(1(0(2(x1)))))) (45)
3(0(0(5(2(x1))))) 2(0(0(3(5(1(x1)))))) (46)
3(0(5(4(2(x1))))) 4(0(3(5(2(1(x1)))))) (47)
3(2(0(1(2(x1))))) 2(1(3(1(0(2(x1)))))) (48)
3(2(0(5(2(x1))))) 2(0(2(3(4(5(x1)))))) (49)
3(2(0(5(2(x1))))) 5(3(0(2(2(2(x1)))))) (50)

Property / Task

Prove or disprove termination.

Answer / Result

Yes.

Proof (by ttt2 @ termCOMP 2023)

1 String Reversal

Since only unary symbols occur, one can reverse all terms and obtains the TRS
2(1(0(0(x1)))) 0(0(1(3(2(x1))))) (51)
2(1(0(0(x1)))) 2(0(0(1(3(x1))))) (52)
2(1(0(0(x1)))) 1(1(3(2(0(0(x1)))))) (53)
4(0(1(0(x1)))) 0(0(4(1(3(x1))))) (54)
4(0(1(0(x1)))) 1(3(0(0(4(3(x1)))))) (55)
4(0(1(0(x1)))) 0(5(0(1(3(4(x1)))))) (56)
4(0(1(0(x1)))) 0(1(3(4(0(5(x1)))))) (57)
5(0(1(0(x1)))) 0(0(1(3(5(3(x1)))))) (58)
5(0(1(0(x1)))) 2(0(0(1(3(5(x1)))))) (59)
2(4(1(0(x1)))) 0(4(1(3(2(x1))))) (60)
2(4(1(0(x1)))) 4(2(1(3(0(4(x1)))))) (61)
2(4(1(0(x1)))) 2(0(1(1(3(4(x1)))))) (62)
4(0(5(0(x1)))) 5(3(0(0(4(x1))))) (63)
4(0(5(0(x1)))) 4(3(0(0(5(x1))))) (64)
5(0(5(0(x1)))) 5(0(0(2(5(3(x1)))))) (65)
5(0(5(0(x1)))) 0(0(4(5(3(5(x1)))))) (66)
5(0(5(0(x1)))) 0(0(4(3(5(5(x1)))))) (67)
2(1(0(2(x1)))) 2(1(4(2(0(x1))))) (68)
2(1(0(2(x1)))) 1(2(2(0(5(2(x1)))))) (69)
2(1(0(2(x1)))) 0(2(2(3(1(3(x1)))))) (70)
2(4(0(2(x1)))) 1(2(2(0(4(x1))))) (71)
2(4(0(2(x1)))) 1(2(1(2(0(4(x1)))))) (72)
2(5(0(2(x1)))) 2(2(5(1(2(0(x1)))))) (73)
2(4(0(3(x1)))) 2(1(1(4(3(0(x1)))))) (74)
2(4(0(3(x1)))) 2(0(1(3(3(4(x1)))))) (75)
2(2(1(0(0(x1))))) 1(2(1(2(0(0(x1)))))) (76)
2(3(1(0(0(x1))))) 4(0(2(1(3(0(x1)))))) (77)
2(3(1(0(0(x1))))) 0(1(3(0(5(2(x1)))))) (78)
2(2(5(0(0(x1))))) 1(2(5(2(0(0(x1)))))) (79)
2(5(0(1(0(x1))))) 5(3(0(1(2(0(x1)))))) (80)
5(5(0(1(0(x1))))) 5(0(0(5(3(1(x1)))))) (81)
5(0(2(1(0(x1))))) 0(1(2(5(0(4(x1)))))) (82)
4(0(3(1(0(x1))))) 0(4(4(3(0(1(x1)))))) (83)
2(4(3(1(0(x1))))) 4(3(0(1(2(4(x1)))))) (84)
2(2(4(1(0(x1))))) 2(4(2(0(1(1(x1)))))) (85)
4(2(4(1(0(x1))))) 4(1(3(2(0(4(x1)))))) (86)
2(3(4(1(0(x1))))) 4(4(0(2(1(3(x1)))))) (87)
5(0(0(3(0(x1))))) 0(0(0(1(3(5(x1)))))) (88)
4(0(1(4(0(x1))))) 0(4(1(2(0(4(x1)))))) (89)
2(2(3(4(0(x1))))) 2(5(3(0(2(4(x1)))))) (90)
4(0(1(5(0(x1))))) 0(0(1(4(2(5(x1)))))) (91)
2(4(1(5(0(x1))))) 2(1(5(3(0(4(x1)))))) (92)
2(1(0(1(2(x1))))) 3(2(0(1(1(2(x1)))))) (93)
2(5(0(4(2(x1))))) 2(5(3(2(4(0(x1)))))) (94)
2(1(0(0(3(x1))))) 2(0(1(5(3(0(x1)))))) (95)
2(5(0(0(3(x1))))) 1(5(3(0(0(2(x1)))))) (96)
2(4(5(0(3(x1))))) 1(2(5(3(0(4(x1)))))) (97)
2(1(0(2(3(x1))))) 2(0(1(3(1(2(x1)))))) (98)
2(5(0(2(3(x1))))) 5(4(3(2(0(2(x1)))))) (99)
2(5(0(2(3(x1))))) 2(2(2(0(3(5(x1)))))) (100)

1.1 Dependency Pair Transformation

The following set of initial dependency pairs has been identified.

There are 116 ruless (increase limit for explicit display).

1.1.1 Dependency Graph Processor

The dependency pairs are split into 1 component.