Certification Problem

Input (TPDB SRS_Standard/Secret_06_SRS/secr7)

The rewrite relation of the following TRS is considered.

Property / Task

Answer / Result

Proof (by ttt2 @ termCOMP 2023)

1 Dependency Pair Transformation

1.1 Dependency Graph Processor

The dependency pairs are split into 1 component.

• The 1^st component contains the pair

  a#(b(c(x1)))	→	a#(a(c(b(x1))))	(8)
  a#(b(c(x1)))	→	a#(c(b(x1)))	(7)

  1.1.1 Reduction Pair Processor with Usable Rules

  Using the linear polynomial interpretation over (2 x 2)-matrices with strict dimension 1 over the arctic semiring over the integers

  [b(x1)]	=	0 0 0 0 · x1 + 0 -∞ -∞ -∞
  [a#(x1)]	=	1 0 -∞ -∞ · x1 + 0 -∞ -∞ -∞
  [c(x1)]	=	0 0 1 1 · x1 + 1 -∞ 2 -∞
  [a(x1)]	=	0 -∞ 1 0 · x1 + 0 -∞ 0 -∞

  together with the usable rules

  a(b(c(x1)))	→	c(b(a(a(c(b(x1))))))	(1)
  a(x1)	→	x1	(2)
  b(x1)	→	x1	(3)
  c(x1)	→	x1	(4)

  (w.r.t. the implicit argument filter of the reduction pair), the pairs

  a#(b(c(x1)))	→	a#(a(c(b(x1))))	(8)
  a#(b(c(x1)))	→	a#(c(b(x1)))	(7)

  could be deleted.

  1.1.1.1 P is empty

  There are no pairs anymore.