The rewrite relation of the following TRS is considered.
a(a(x1)) | → | b(a(c(x1))) | (1) |
b(b(x1)) | → | a(a(x1)) | (2) |
c(b(x1)) | → | a(x1) | (3) |
a#(a(x1)) | → | c#(x1) | (4) |
a#(a(x1)) | → | a#(c(x1)) | (5) |
a#(a(x1)) | → | b#(a(c(x1))) | (6) |
b#(b(x1)) | → | a#(x1) | (7) |
b#(b(x1)) | → | a#(a(x1)) | (8) |
c#(b(x1)) | → | a#(x1) | (9) |
π(b#) | = | { 1 } |
π(c#) | = | { 1, 1 } |
π(a#) | = | { 1 } |
π(b) | = | { 1, 1 } |
π(c) | = | { 1 } |
π(a) | = | { 1, 1 } |
a#(a(x1)) | → | a#(c(x1)) | (5) |
b#(b(x1)) | → | a#(x1) | (7) |
c#(b(x1)) | → | a#(x1) | (9) |
The dependency pairs are split into 1 component.
b#(b(x1)) | → | a#(a(x1)) | (8) |
a#(a(x1)) | → | b#(a(c(x1))) | (6) |
[c(x1)] | = |
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[a#(x1)] | = |
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[b#(x1)] | = |
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[a(x1)] | = |
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[b(x1)] | = |
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a(a(x1)) | → | b(a(c(x1))) | (1) |
b(b(x1)) | → | a(a(x1)) | (2) |
c(b(x1)) | → | a(x1) | (3) |
a#(a(x1)) | → | b#(a(c(x1))) | (6) |
The dependency pairs are split into 0 components.