Certification Problem

Input (TPDB SRS_Standard/Wenzel_16/abbaaaa-aaaaabbaabbabb.srs)

The rewrite relation of the following TRS is considered.

a(b(b(a(a(a(a(x1))))))) a(a(a(a(a(b(b(a(a(b(b(a(b(b(x1)))))))))))))) (1)

Property / Task

Prove or disprove termination.

Answer / Result

Yes.

Proof (by ttt2 @ termCOMP 2023)

1 Semantic Labeling

Root-labeling is applied.

We obtain the labeled TRS
ab(bb(ba(aa(aa(aa(aa(x1))))))) aa(aa(aa(aa(ab(bb(ba(aa(ab(bb(ba(ab(bb(ba(x1)))))))))))))) (2)
ab(bb(ba(aa(aa(aa(ab(x1))))))) aa(aa(aa(aa(ab(bb(ba(aa(ab(bb(ba(ab(bb(bb(x1)))))))))))))) (3)

1.1 Dependency Pair Transformation

The following set of initial dependency pairs has been identified.
ab#(bb(ba(aa(aa(aa(aa(x1))))))) ab#(bb(ba(x1))) (4)
ab#(bb(ba(aa(aa(aa(aa(x1))))))) ab#(bb(ba(ab(bb(ba(x1)))))) (5)
ab#(bb(ba(aa(aa(aa(aa(x1))))))) ab#(bb(ba(aa(ab(bb(ba(ab(bb(ba(x1)))))))))) (6)
ab#(bb(ba(aa(aa(aa(ab(x1))))))) ab#(bb(bb(x1))) (7)
ab#(bb(ba(aa(aa(aa(ab(x1))))))) ab#(bb(ba(ab(bb(bb(x1)))))) (8)
ab#(bb(ba(aa(aa(aa(ab(x1))))))) ab#(bb(ba(aa(ab(bb(ba(ab(bb(bb(x1)))))))))) (9)

1.1.1 Dependency Graph Processor

The dependency pairs are split into 1 component.