Certification Problem

Input (TPDB SRS_Standard/Zantema_04/z065)

The rewrite relation of the following TRS is considered.

0(*(x1)) *(1(x1)) (1)
1(*(x1)) 0(#(x1)) (2)
#(0(x1)) 0(#(x1)) (3)
#(1(x1)) 1(#(x1)) (4)
#($(x1)) *($(x1)) (5)
#(#(x1)) #(x1) (6)
#(*(x1)) *(x1) (7)

Property / Task

Prove or disprove termination.

Answer / Result

Yes.

Proof (by ttt2 @ termCOMP 2023)

1 Rule Removal

Using the Knuth Bendix order with w0 = 1 and the following precedence and weight functions
prec($) = 7 weight($) = 2
prec(#) = 3 weight(#) = 5
prec(1) = 2 weight(1) = 1
prec(0) = 1 weight(0) = 1
prec(*) = 0 weight(*) = 5
all of the following rules can be deleted.
0(*(x1)) *(1(x1)) (1)
1(*(x1)) 0(#(x1)) (2)
#(0(x1)) 0(#(x1)) (3)
#(1(x1)) 1(#(x1)) (4)
#($(x1)) *($(x1)) (5)
#(#(x1)) #(x1) (6)
#(*(x1)) *(x1) (7)

1.1 R is empty

There are no rules in the TRS. Hence, it is terminating.