Certification Problem

Input (TPDB TRS_Innermost/AG01_innermost/#4.19)

The rewrite relation of the following TRS is considered.

f(x,c(x),c(y)) f(y,y,f(y,x,y)) (1)
f(s(x),y,z) f(x,s(c(y)),c(z)) (2)
f(c(x),x,y) c(y) (3)
g(x,y) x (4)
g(x,y) y (5)
The evaluation strategy is innermost.

Property / Task

Prove or disprove termination.

Answer / Result

Yes.

Proof (by AProVE @ termCOMP 2023)

1 Dependency Pair Transformation

The following set of initial dependency pairs has been identified.
f#(x,c(x),c(y)) f#(y,y,f(y,x,y)) (6)
f#(x,c(x),c(y)) f#(y,x,y) (7)
f#(s(x),y,z) f#(x,s(c(y)),c(z)) (8)

1.1 Dependency Graph Processor

The dependency pairs are split into 2 components.