Certification Problem

Input (TPDB TRS_Standard/AProVE_06/quot)

The rewrite relation of the following TRS is considered.

Property / Task

Answer / Result

Proof (by AProVE @ termCOMP 2023)

1 Switch to Innermost Termination

The TRS is overlay and locally confluent:

Hence, it suffices to show innermost termination in the following.

1.1 Dependency Pair Transformation

1.1.1 Dependency Graph Processor

The dependency pairs are split into 3 components.

• The 1^st component contains the pair

  quot#(x,y)	→	if_quot#(minus(x,y),y,le(y,0),le(y,x))	(14)
  if_quot#(x,y,false,true)	→	quot#(x,y)	(18)

  1.1.1.1 Usable Rules Processor

  We restrict the rewrite rules to the following usable rules of the DP problem.

  minus(x,x)	→	0	(1)
  minus(0,x)	→	0	(2)
  minus(x,0)	→	x	(3)
  minus(s(x),s(y))	→	minus(x,y)	(4)
  le(0,y)	→	true	(5)
  le(s(x),0)	→	false	(6)
  le(s(x),s(y))	→	le(x,y)	(7)

  1.1.1.1.1 Innermost Lhss Removal Processor

  We restrict the innermost strategy to the following left hand sides.

  minus(x0,x0)

  minus(0,x0)

  minus(x0,0)

  minus(s(x0),s(x1))

  le(0,x0)

  le(s(x0),0)

  le(s(x0),s(x1))

  1.1.1.1.1.1 Narrowing Processor

  We consider all narrowings of the pair below position 3 to get the following set of pairs

  quot#(y0,0)	→	if_quot#(minus(y0,0),0,true,le(0,y0))	(19)
  quot#(y0,s(x0))	→	if_quot#(minus(y0,s(x0)),s(x0),false,le(s(x0),y0))	(20)

  1.1.1.1.1.1.1 Dependency Graph Processor

  The dependency pairs are split into 1 component.

  • The 1^st component contains the pair

    quot#(y0,s(x0))	→	if_quot#(minus(y0,s(x0)),s(x0),false,le(s(x0),y0))	(20)
    if_quot#(x,y,false,true)	→	quot#(x,y)	(18)

    1.1.1.1.1.1.1.1 Narrowing Processor

    We consider all narrowings of the pair below position 4 to get the following set of pairs

    quot#(0,s(x0))	→	if_quot#(minus(0,s(x0)),s(x0),false,false)	(21)
    quot#(s(x1),s(x0))	→	if_quot#(minus(s(x1),s(x0)),s(x0),false,le(x0,x1))	(22)

    1.1.1.1.1.1.1.1.1 Dependency Graph Processor

    The dependency pairs are split into 1 component.

    • The 1^st component contains the pair

      quot#(s(x1),s(x0))	→	if_quot#(minus(s(x1),s(x0)),s(x0),false,le(x0,x1))	(22)
      if_quot#(x,y,false,true)	→	quot#(x,y)	(18)

      1.1.1.1.1.1.1.1.1.1 Narrowing Processor

      We consider all narrowings of the pair below position 1 to get the following set of pairs

      quot#(s(y0),s(y0))	→	if_quot#(0,s(y0),false,le(y0,y0))	(23)
      quot#(s(x0),s(x1))	→	if_quot#(minus(x0,x1),s(x1),false,le(x1,x0))	(24)

      1.1.1.1.1.1.1.1.1.1.1 Instantiation Processor

      We instantiate the pair to the following set of pairs

      if_quot#(0,s(z0),false,true)	→	quot#(0,s(z0))	(25)
      if_quot#(y_0,s(z1),false,true)	→	quot#(y_0,s(z1))	(26)

      1.1.1.1.1.1.1.1.1.1.1.1 Dependency Graph Processor

      The dependency pairs are split into 1 component.

      • The 1^st component contains the pair

        if_quot#(y_0,s(z1),false,true)	→	quot#(y_0,s(z1))	(26)
        quot#(s(y0),s(y0))	→	if_quot#(0,s(y0),false,le(y0,y0))	(23)
        quot#(s(x0),s(x1))	→	if_quot#(minus(x0,x1),s(x1),false,le(x1,x0))	(24)

        1.1.1.1.1.1.1.1.1.1.1.1.1 Forward Instantiation Processor

        We instantiate the pair to the following set of pairs

        if_quot#(s(y_0),s(x1),false,true)

        →

        quot#(s(y_0),s(x1))

        (27)

        1.1.1.1.1.1.1.1.1.1.1.1.1.1 Dependency Graph Processor

        The dependency pairs are split into 1 component.

        • The 1^st component contains the pair

          quot#(s(x0),s(x1))	→	if_quot#(minus(x0,x1),s(x1),false,le(x1,x0))	(24)
          if_quot#(s(y_0),s(x1),false,true)	→	quot#(s(y_0),s(x1))	(27)

          1.1.1.1.1.1.1.1.1.1.1.1.1.1.1 Reduction Pair Processor with Usable Rules

          Using the Knuth Bendix order with w0 = 1 and the following precedence and weight functions

          prec(s)	=	0		weight(s)	=	1
          prec(0)	=	1		weight(0)	=	1

          in combination with the following argument filter

          π(quot#)	=	1
          π(s)	=	[1]
          π(if_quot#)	=	1
          π(minus)	=	1
          π(0)	=	[]

          together with the usable rules

          minus(x,x)	→	0	(1)
          minus(0,x)	→	0	(2)
          minus(x,0)	→	x	(3)
          minus(s(x),s(y))	→	minus(x,y)	(4)

          (w.r.t. the implicit argument filter of the reduction pair), the pair

          quot#(s(x0),s(x1))

          →

          if_quot#(minus(x0,x1),s(x1),false,le(x1,x0))

          (24)

          could be deleted.

          1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1 Usable Rules Processor

          We restrict the rewrite rules to the following usable rules of the DP problem.

          There are no rules.

          1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1 Innermost Lhss Removal Processor

          We restrict the innermost strategy to the following left hand sides.

          There are no lhss.

          1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1 Size-Change Termination

          Using size-change termination in combination with the subterm criterion one obtains the following initial size-change graphs.

          if_quot#(s(y_0),s(x1),false,true)	→	quot#(s(y_0),s(x1))	(27)
          1	≥	1
          2	≥	2

          As there is no critical graph in the transitive closure, there are no infinite chains.

• The 2^nd component contains the pair

  minus#(s(x),s(y))

  →

  minus#(x,y)

  (12)

  1.1.1.2 Usable Rules Processor

  We restrict the rewrite rules to the following usable rules of the DP problem.

  There are no rules.

  1.1.1.2.1 Innermost Lhss Removal Processor

  We restrict the innermost strategy to the following left hand sides.

  There are no lhss.

  1.1.1.2.1.1 Size-Change Termination

  Using size-change termination in combination with the subterm criterion one obtains the following initial size-change graphs.

  minus#(s(x),s(y))	→	minus#(x,y)	(12)
  1	>	1
  2	>	2

  As there is no critical graph in the transitive closure, there are no infinite chains.

• The 3^rd component contains the pair

  le#(s(x),s(y))

  →

  le#(x,y)

  (13)

  1.1.1.3 Usable Rules Processor

  We restrict the rewrite rules to the following usable rules of the DP problem.

  There are no rules.

  1.1.1.3.1 Innermost Lhss Removal Processor

  We restrict the innermost strategy to the following left hand sides.

  There are no lhss.

  1.1.1.3.1.1 Size-Change Termination

  Using size-change termination in combination with the subterm criterion one obtains the following initial size-change graphs.

  le#(s(x),s(y))	→	le#(x,y)	(13)
  1	>	1
  2	>	2

  As there is no critical graph in the transitive closure, there are no infinite chains.