The rewrite relation of the following TRS is considered.
| f(a,f(x,a)) | → | f(x,f(f(f(a,a),a),a)) | (1) |
The TRS is overlay and locally confluent:
10Hence, it suffices to show innermost termination in the following.
| f#(a,f(x,a)) | → | f#(x,f(f(f(a,a),a),a)) | (2) |
| f#(a,f(x,a)) | → | f#(f(f(a,a),a),a) | (3) |
| f#(a,f(x,a)) | → | f#(f(a,a),a) | (4) |
| f#(a,f(x,a)) | → | f#(a,a) | (5) |
The dependency pairs are split into 1 component.
| f#(a,f(x,a)) | → | f#(x,f(f(f(a,a),a),a)) | (2) |
We restrict the rewrite rules to the following usable rules of the DP problem.
There are no rules.
| [f#(x1, x2)] | = | 1 + x1 + x2 |
| [a] | = | 2 |
| [f(x1, x2)] | = | -1 + x1 |
| f#(a,f(x,a)) | → | f#(x,f(f(f(a,a),a),a)) | (2) |
There are no pairs anymore.