Certification Problem

Input (TPDB TRS_Standard/AG01/#3.49)

The rewrite relation of the following TRS is considered.

f(c(s(x),y)) f(c(x,s(y))) (1)
f(c(s(x),s(y))) g(c(x,y)) (2)
g(c(x,s(y))) g(c(s(x),y)) (3)
g(c(s(x),s(y))) f(c(x,y)) (4)

Property / Task

Prove or disprove termination.

Answer / Result

Yes.

Proof (by NaTT @ termCOMP 2023)

1 Dependency Pair Transformation

The following set of initial dependency pairs has been identified.
g#(c(x,s(y))) g#(c(s(x),y)) (5)
f#(c(s(x),y)) f#(c(x,s(y))) (6)
f#(c(s(x),s(y))) g#(c(x,y)) (7)
g#(c(s(x),s(y))) f#(c(x,y)) (8)

1.1 Dependency Graph Processor

The dependency pairs are split into 1 component.