Certification Problem

Input (TPDB TRS_Standard/AotoYamada_05/005)

The rewrite relation of the following TRS is considered.

app(app(plus,0),y) y (1)
app(app(plus,app(s,x)),y) app(s,app(app(plus,x),y)) (2)
app(app(app(curry,f),x),y) app(app(f,x),y) (3)
add app(curry,plus) (4)

Property / Task

Prove or disprove termination.

Answer / Result

Yes.

Proof (by NaTT @ termCOMP 2023)

1 Dependency Pair Transformation

The following set of initial dependency pairs has been identified.
app#(app(plus,app(s,x)),y) app#(app(plus,x),y) (5)
add# app#(curry,plus) (6)
app#(app(app(curry,f),x),y) app#(f,x) (7)
app#(app(plus,app(s,x)),y) app#(plus,x) (8)
app#(app(plus,app(s,x)),y) app#(s,app(app(plus,x),y)) (9)
app#(app(app(curry,f),x),y) app#(app(f,x),y) (10)

1.1 Dependency Graph Processor

The dependency pairs are split into 2 components.