The rewrite relation of the following TRS is considered.
| app(app(F,app(app(F,f),x)),x) | → | app(app(F,app(G,app(app(F,f),x))),app(f,x)) | (1) |
| app#(app(F,app(app(F,f),x)),x) | → | app#(F,app(G,app(app(F,f),x))) | (2) |
| app#(app(F,app(app(F,f),x)),x) | → | app#(G,app(app(F,f),x)) | (3) |
| app#(app(F,app(app(F,f),x)),x) | → | app#(app(F,app(G,app(app(F,f),x))),app(f,x)) | (4) |
| app#(app(F,app(app(F,f),x)),x) | → | app#(f,x) | (5) |
The dependency pairs are split into 1 component.
| app#(app(F,app(app(F,f),x)),x) | → | app#(f,x) | (5) |
| [G] | = | 0 |
| [F] | = | 23676 |
| [app#(x1, x2)] | = | x1 + x2 + 0 |
| [app(x1, x2)] | = | x1 + x2 + 0 |
| app#(app(F,app(app(F,f),x)),x) | → | app#(f,x) | (5) |
The dependency pairs are split into 0 components.