The rewrite relation of the following TRS is considered.
app(app(map,f),nil) |
→ |
nil |
(1) |
app(app(map,f),app(app(cons,x),xs)) |
→ |
app(app(cons,app(f,x)),app(app(map,f),xs)) |
(2) |
app(app(le,0),y) |
→ |
true |
(3) |
app(app(le,app(s,x)),0) |
→ |
false |
(4) |
app(app(le,app(s,x)),app(s,y)) |
→ |
app(app(le,x),y) |
(5) |
app(app(maxlist,x),app(app(cons,y),ys)) |
→ |
app(app(if,app(app(le,x),y)),app(app(maxlist,y),ys)) |
(6) |
app(app(maxlist,x),nil) |
→ |
x |
(7) |
app(height,app(app(node,x),xs)) |
→ |
app(s,app(app(maxlist,0),app(app(map,height),xs))) |
(8) |
app#(app(map,f),app(app(cons,x),xs)) |
→ |
app#(cons,app(f,x)) |
(9) |
app#(app(maxlist,x),app(app(cons,y),ys)) |
→ |
app#(if,app(app(le,x),y)) |
(10) |
app#(height,app(app(node,x),xs)) |
→ |
app#(s,app(app(maxlist,0),app(app(map,height),xs))) |
(11) |
app#(app(maxlist,x),app(app(cons,y),ys)) |
→ |
app#(app(maxlist,y),ys) |
(12) |
app#(app(le,app(s,x)),app(s,y)) |
→ |
app#(app(le,x),y) |
(13) |
app#(app(le,app(s,x)),app(s,y)) |
→ |
app#(le,x) |
(14) |
app#(height,app(app(node,x),xs)) |
→ |
app#(app(maxlist,0),app(app(map,height),xs)) |
(15) |
app#(app(maxlist,x),app(app(cons,y),ys)) |
→ |
app#(app(le,x),y) |
(16) |
app#(app(maxlist,x),app(app(cons,y),ys)) |
→ |
app#(maxlist,y) |
(17) |
app#(app(maxlist,x),app(app(cons,y),ys)) |
→ |
app#(app(if,app(app(le,x),y)),app(app(maxlist,y),ys)) |
(18) |
app#(height,app(app(node,x),xs)) |
→ |
app#(map,height) |
(19) |
app#(height,app(app(node,x),xs)) |
→ |
app#(app(map,height),xs) |
(20) |
app#(app(map,f),app(app(cons,x),xs)) |
→ |
app#(f,x) |
(21) |
app#(app(map,f),app(app(cons,x),xs)) |
→ |
app#(app(cons,app(f,x)),app(app(map,f),xs)) |
(22) |
app#(app(maxlist,x),app(app(cons,y),ys)) |
→ |
app#(le,x) |
(23) |
app#(height,app(app(node,x),xs)) |
→ |
app#(maxlist,0) |
(24) |
app#(app(map,f),app(app(cons,x),xs)) |
→ |
app#(app(map,f),xs) |
(25) |
The dependency pairs are split into 3
components.