The rewrite relation of the following TRS is considered.
h(f(x),y) | → | f(g(x,y)) | (1) |
g(x,y) | → | h(x,y) | (2) |
h#(f(x),y) | → | g#(x,y) | (3) |
g#(x,y) | → | h#(x,y) | (4) |
The dependency pairs are split into 1 component.
g#(x,y) | → | h#(x,y) | (4) |
h#(f(x),y) | → | g#(x,y) | (3) |
[h(x1, x2)] | = | 0 |
[f(x1)] | = | x1 + 2 |
[h#(x1, x2)] | = | x1 + 0 |
[g#(x1, x2)] | = | x1 + 1 |
[g(x1, x2)] | = | 0 |
g#(x,y) | → | h#(x,y) | (4) |
h#(f(x),y) | → | g#(x,y) | (3) |
The dependency pairs are split into 0 components.