The rewrite relation of the following TRS is considered.
f(g(x,y),f(y,y)) | → | f(g(y,x),y) | (1) |
f#(g(x,y),f(y,y)) | → | f#(g(y,x),y) | (2) |
The dependency pairs are split into 1 component.
f#(g(x,y),f(y,y)) | → | f#(g(y,x),y) | (2) |
[f(x1, x2)] | = | x1 + 1 |
[f#(x1, x2)] | = | x2 + 0 |
[g(x1, x2)] | = | 0 |
f#(g(x,y),f(y,y)) | → | f#(g(y,x),y) | (2) |
The dependency pairs are split into 0 components.