Certification Problem
Input (TPDB TRS_Standard/SK90/2.35)
The rewrite relation of the following TRS is considered.
and(x,false) |
→ |
false |
(1) |
and(x,not(false)) |
→ |
x |
(2) |
not(not(x)) |
→ |
x |
(3) |
implies(false,y) |
→ |
not(false) |
(4) |
implies(x,false) |
→ |
not(x) |
(5) |
implies(not(x),not(y)) |
→ |
implies(y,and(x,y)) |
(6) |
Property / Task
Prove or disprove termination.Answer / Result
Yes.Proof (by NaTT @ termCOMP 2023)
1 Dependency Pair Transformation
The following set of initial dependency pairs has been identified.
implies#(not(x),not(y)) |
→ |
and#(x,y) |
(7) |
implies#(x,false) |
→ |
not#(x) |
(8) |
implies#(not(x),not(y)) |
→ |
implies#(y,and(x,y)) |
(9) |
implies#(false,y) |
→ |
not#(false) |
(10) |
1.1 Dependency Graph Processor
The dependency pairs are split into 1
component.