Certification Problem

Input (TPDB TRS_Standard/Secret_06_TRS/gen-9)

The rewrite relation of the following TRS is considered.

c(c(z,y,a),a,a) b(z,y) (1)
f(c(x,y,z)) c(z,f(b(y,z)),a) (2)
b(z,b(c(a,y,a),f(f(x)))) c(c(y,a,z),z,x) (3)

Property / Task

Prove or disprove termination.

Answer / Result

Yes.

Proof (by NaTT @ termCOMP 2023)

1 Dependency Pair Transformation

The following set of initial dependency pairs has been identified.
f#(c(x,y,z)) f#(b(y,z)) (4)
c#(c(z,y,a),a,a) b#(z,y) (5)
b#(z,b(c(a,y,a),f(f(x)))) c#(y,a,z) (6)
f#(c(x,y,z)) b#(y,z) (7)
f#(c(x,y,z)) c#(z,f(b(y,z)),a) (8)
b#(z,b(c(a,y,a),f(f(x)))) c#(c(y,a,z),z,x) (9)

1.1 Dependency Graph Processor

The dependency pairs are split into 2 components.