Certification Problem

Input (TPDB TRS_Standard/Applicative_first_order_05/hydra)

The rewrite relation of the following TRS is considered.

app(f,app(app(cons,nil),y)) y (1)
app(f,app(app(cons,app(f,app(app(cons,nil),y))),z)) app(app(app(copy,n),y),z) (2)
app(app(app(copy,0),y),z) app(f,z) (3)
app(app(app(copy,app(s,x)),y),z) app(app(app(copy,x),y),app(app(cons,app(f,y)),z)) (4)
app(app(map,fun),nil) nil (5)
app(app(map,fun),app(app(cons,x),xs)) app(app(cons,app(fun,x)),app(app(map,fun),xs)) (6)
app(app(filter,fun),nil) nil (7)
app(app(filter,fun),app(app(cons,x),xs)) app(app(app(app(filter2,app(fun,x)),fun),x),xs) (8)
app(app(app(app(filter2,true),fun),x),xs) app(app(cons,x),app(app(filter,fun),xs)) (9)
app(app(app(app(filter2,false),fun),x),xs) app(app(filter,fun),xs) (10)

Property / Task

Prove or disprove termination.

Answer / Result

Yes.

Proof (by ttt2 @ termCOMP 2023)

1 Dependency Pair Transformation

The following set of initial dependency pairs has been identified.
app#(f,app(app(cons,app(f,app(app(cons,nil),y))),z)) app#(copy,n) (11)
app#(f,app(app(cons,app(f,app(app(cons,nil),y))),z)) app#(app(copy,n),y) (12)
app#(f,app(app(cons,app(f,app(app(cons,nil),y))),z)) app#(app(app(copy,n),y),z) (13)
app#(app(app(copy,0),y),z) app#(f,z) (14)
app#(app(app(copy,app(s,x)),y),z) app#(f,y) (15)
app#(app(app(copy,app(s,x)),y),z) app#(cons,app(f,y)) (16)
app#(app(app(copy,app(s,x)),y),z) app#(app(cons,app(f,y)),z) (17)
app#(app(app(copy,app(s,x)),y),z) app#(copy,x) (18)
app#(app(app(copy,app(s,x)),y),z) app#(app(copy,x),y) (19)
app#(app(app(copy,app(s,x)),y),z) app#(app(app(copy,x),y),app(app(cons,app(f,y)),z)) (20)
app#(app(map,fun),app(app(cons,x),xs)) app#(app(map,fun),xs) (21)
app#(app(map,fun),app(app(cons,x),xs)) app#(fun,x) (22)
app#(app(map,fun),app(app(cons,x),xs)) app#(cons,app(fun,x)) (23)
app#(app(map,fun),app(app(cons,x),xs)) app#(app(cons,app(fun,x)),app(app(map,fun),xs)) (24)
app#(app(filter,fun),app(app(cons,x),xs)) app#(fun,x) (25)
app#(app(filter,fun),app(app(cons,x),xs)) app#(filter2,app(fun,x)) (26)
app#(app(filter,fun),app(app(cons,x),xs)) app#(app(filter2,app(fun,x)),fun) (27)
app#(app(filter,fun),app(app(cons,x),xs)) app#(app(app(filter2,app(fun,x)),fun),x) (28)
app#(app(filter,fun),app(app(cons,x),xs)) app#(app(app(app(filter2,app(fun,x)),fun),x),xs) (29)
app#(app(app(app(filter2,true),fun),x),xs) app#(filter,fun) (30)
app#(app(app(app(filter2,true),fun),x),xs) app#(app(filter,fun),xs) (31)
app#(app(app(app(filter2,true),fun),x),xs) app#(cons,x) (32)
app#(app(app(app(filter2,true),fun),x),xs) app#(app(cons,x),app(app(filter,fun),xs)) (33)
app#(app(app(app(filter2,false),fun),x),xs) app#(filter,fun) (34)
app#(app(app(app(filter2,false),fun),x),xs) app#(app(filter,fun),xs) (35)

1.1 Dependency Graph Processor

The dependency pairs are split into 2 components.