Certification Problem
Input (TPDB TRS_Standard/Rubio_04/bn122)
The rewrite relation of the following TRS is considered.
plus(plus(X,Y),Z) |
→ |
plus(X,plus(Y,Z)) |
(1) |
times(X,s(Y)) |
→ |
plus(X,times(Y,X)) |
(2) |
Property / Task
Prove or disprove termination.Answer / Result
Yes.Proof (by ttt2 @ termCOMP 2023)
1 Rule Removal
Using the
linear polynomial interpretation over the naturals
[s(x1)] |
= |
5 · x1 + 3 |
[plus(x1, x2)] |
= |
2 · x1 + 1 · x2 + 16 |
[times(x1, x2)] |
= |
16 · x1 + 14 · x2 + 0 |
all of the following rules can be deleted.
plus(plus(X,Y),Z) |
→ |
plus(X,plus(Y,Z)) |
(1) |
times(X,s(Y)) |
→ |
plus(X,times(Y,X)) |
(2) |
1.1 R is empty
There are no rules in the TRS. Hence, it is terminating.