Certification Problem

Input (TPDB TRS_Standard/Strategy_removed_AG01/#4.32)

The rewrite relation of the following TRS is considered.

f(x,c(y)) → f(x,s(f(y,y))) (1)
f(s(x),s(y)) → f(x,s(c(s(y)))) (2)

Property / Task

Prove or disprove termination.

Answer / Result

Yes.

Proof (by ttt2 @ termCOMP 2023)

1 Rule Removal

Using the linear polynomial interpretation over (3 x 3)-matrices with strict dimension 1 over the naturals
[f(x1, x2)] =
1 0 0
1 0 0
0 0 0
· x1 +
1 1 0
0 1 0
0 0 0
· x2 +
0 0 0
0 0 0
0 0 0
[c(x1)] =
1 0 0
1 1 1
0 0 0
· x1 +
0 0 0
1 0 0
0 0 0
[s(x1)] =
1 0 0
0 0 0
1 1 0
· x1 +
0 0 0
0 0 0
0 0 0
all of the following rules can be deleted.
f(x,c(y)) → f(x,s(f(y,y))) (1)

1.1 Rule Removal

Using the Knuth Bendix order with w0 = 1 and the following precedence and weight functions
prec(s) = 0 weight(s) = 2
prec(f) = 2 weight(f) = 0
prec(c) = 3 weight(c) = 0
all of the following rules can be deleted.
f(s(x),s(y)) → f(x,s(c(s(y)))) (2)

1.1.1 R is empty

There are no rules in the TRS. Hence, it is terminating.