Certification Problem
Input (TPDB TRS_Standard/Transformed_CSR_04/Ex4_7_56_Bor03_Z)
The rewrite relation of the following TRS is considered.
from(X) |
→ |
cons(X,n__from(s(X))) |
(1) |
after(0,XS) |
→ |
XS |
(2) |
after(s(N),cons(X,XS)) |
→ |
after(N,activate(XS)) |
(3) |
from(X) |
→ |
n__from(X) |
(4) |
activate(n__from(X)) |
→ |
from(X) |
(5) |
activate(X) |
→ |
X |
(6) |
Property / Task
Prove or disprove termination.Answer / Result
Yes.Proof (by ttt2 @ termCOMP 2023)
1 Rule Removal
Using the
Weighted Path Order with the following precedence and status
prec(activate) |
= |
5 |
|
status(activate) |
= |
[1] |
|
list-extension(activate) |
= |
Lex |
prec(after) |
= |
6 |
|
status(after) |
= |
[1, 2] |
|
list-extension(after) |
= |
Lex |
prec(0) |
= |
0 |
|
status(0) |
= |
[] |
|
list-extension(0) |
= |
Lex |
prec(cons) |
= |
0 |
|
status(cons) |
= |
[2, 1] |
|
list-extension(cons) |
= |
Lex |
prec(n__from) |
= |
0 |
|
status(n__from) |
= |
[1] |
|
list-extension(n__from) |
= |
Lex |
prec(s) |
= |
0 |
|
status(s) |
= |
[1] |
|
list-extension(s) |
= |
Lex |
prec(from) |
= |
4 |
|
status(from) |
= |
[1] |
|
list-extension(from) |
= |
Lex |
and the following
Max-polynomial interpretation
[activate(x1)] |
=
|
max(1, 0 + 1 · x1) |
[after(x1, x2)] |
=
|
max(2, 0 + 1 · x1, 0 + 1 · x2) |
[0] |
=
|
max(0) |
[cons(x1, x2)] |
=
|
max(1, 0 + 1 · x1, 0 + 1 · x2) |
[n__from(x1)] |
=
|
max(1, 0 + 1 · x1) |
[s(x1)] |
=
|
max(0, 0 + 1 · x1) |
[from(x1)] |
=
|
max(1, 0 + 1 · x1) |
all of the following rules can be deleted.
from(X) |
→ |
cons(X,n__from(s(X))) |
(1) |
after(0,XS) |
→ |
XS |
(2) |
after(s(N),cons(X,XS)) |
→ |
after(N,activate(XS)) |
(3) |
from(X) |
→ |
n__from(X) |
(4) |
activate(n__from(X)) |
→ |
from(X) |
(5) |
activate(X) |
→ |
X |
(6) |
1.1 R is empty
There are no rules in the TRS. Hence, it is terminating.