YES(O(1),O(n^1)) We are left with following problem, upon which TcT provides the certificate YES(O(1),O(n^1)). Strict Trs: { *(x, +(y, z)) -> +(*(x, y), *(x, z)) } Obligation: innermost runtime complexity Answer: YES(O(1),O(n^1)) We add the following innermost weak dependency pairs: Strict DPs: { *^#(x, +(y, z)) -> c_1(*^#(x, y), *^#(x, z)) } and mark the set of starting terms. We are left with following problem, upon which TcT provides the certificate YES(O(1),O(n^1)). Strict DPs: { *^#(x, +(y, z)) -> c_1(*^#(x, y), *^#(x, z)) } Strict Trs: { *(x, +(y, z)) -> +(*(x, y), *(x, z)) } Obligation: innermost runtime complexity Answer: YES(O(1),O(n^1)) No rule is usable, rules are removed from the input problem. We are left with following problem, upon which TcT provides the certificate YES(O(1),O(n^1)). Strict DPs: { *^#(x, +(y, z)) -> c_1(*^#(x, y), *^#(x, z)) } Obligation: innermost runtime complexity Answer: YES(O(1),O(n^1)) The weightgap principle applies (using the following constant growth matrix-interpretation) The following argument positions are usable: Uargs(c_1) = {1, 2} TcT has computed the following constructor-restricted matrix interpretation. [+](x1, x2) = [1 0] x1 + [1 0] x2 + [1] [0 0] [0 0] [0] [*^#](x1, x2) = [1 0] x2 + [0] [0 0] [0] [c_1](x1, x2) = [1 0] x1 + [1 0] x2 + [0] [0 1] [0 1] [0] The following symbols are considered usable {*^#} The order satisfies the following ordering constraints: [*^#(x, +(y, z))] = [1 0] y + [1 0] z + [1] [0 0] [0 0] [0] > [1 0] y + [1 0] z + [0] [0 0] [0 0] [0] = [c_1(*^#(x, y), *^#(x, z))] Further, it can be verified that all rules not oriented are covered by the weightgap condition. We are left with following problem, upon which TcT provides the certificate YES(O(1),O(1)). Weak DPs: { *^#(x, +(y, z)) -> c_1(*^#(x, y), *^#(x, z)) } Obligation: innermost runtime complexity Answer: YES(O(1),O(1)) The following weak DPs constitute a sub-graph of the DG that is closed under successors. The DPs are removed. { *^#(x, +(y, z)) -> c_1(*^#(x, y), *^#(x, z)) } We are left with following problem, upon which TcT provides the certificate YES(O(1),O(1)). Rules: Empty Obligation: innermost runtime complexity Answer: YES(O(1),O(1)) Empty rules are trivially bounded Hurray, we answered YES(O(1),O(n^1))