YES(O(1),O(n^1)) We are left with following problem, upon which TcT provides the certificate YES(O(1),O(n^1)). Strict Trs: { or(x, true()) -> true() , or(true(), y) -> true() , or(false(), false()) -> false() , mem(x, nil()) -> false() , mem(x, set(y)) -> =(x, y) , mem(x, union(y, z)) -> or(mem(x, y), mem(x, z)) } Obligation: innermost runtime complexity Answer: YES(O(1),O(n^1)) The weightgap principle applies (using the following nonconstant growth matrix-interpretation) The following argument positions are usable: Uargs(or) = {1, 2} TcT has computed the following matrix interpretation satisfying not(EDA) and not(IDA(1)). [or](x1, x2) = [1] x1 + [1] x2 + [7] [true] = [7] [false] = [3] [mem](x1, x2) = [1] x2 + [3] [nil] = [7] [set](x1) = [1] x1 + [7] [=](x1, x2) = [1] x2 + [1] [union](x1, x2) = [1] x1 + [1] x2 + [7] The following symbols are considered usable {or, mem} The order satisfies the following ordering constraints: [or(x, true())] = [1] x + [14] > [7] = [true()] [or(true(), y)] = [1] y + [14] > [7] = [true()] [or(false(), false())] = [13] > [3] = [false()] [mem(x, nil())] = [10] > [3] = [false()] [mem(x, set(y))] = [1] y + [10] > [1] y + [1] = [=(x, y)] [mem(x, union(y, z))] = [1] y + [1] z + [10] ? [1] y + [1] z + [13] = [or(mem(x, y), mem(x, z))] Further, it can be verified that all rules not oriented are covered by the weightgap condition. We are left with following problem, upon which TcT provides the certificate YES(O(1),O(n^1)). Strict Trs: { mem(x, union(y, z)) -> or(mem(x, y), mem(x, z)) } Weak Trs: { or(x, true()) -> true() , or(true(), y) -> true() , or(false(), false()) -> false() , mem(x, nil()) -> false() , mem(x, set(y)) -> =(x, y) } Obligation: innermost runtime complexity Answer: YES(O(1),O(n^1)) The weightgap principle applies (using the following nonconstant growth matrix-interpretation) The following argument positions are usable: Uargs(or) = {1, 2} TcT has computed the following matrix interpretation satisfying not(EDA) and not(IDA(1)). [or](x1, x2) = [1] x1 + [1] x2 + [0] [true] = [7] [false] = [4] [mem](x1, x2) = [1] x2 + [0] [nil] = [7] [set](x1) = [1] x1 + [7] [=](x1, x2) = [1] x2 + [7] [union](x1, x2) = [1] x1 + [1] x2 + [7] The following symbols are considered usable {or, mem} The order satisfies the following ordering constraints: [or(x, true())] = [1] x + [7] >= [7] = [true()] [or(true(), y)] = [1] y + [7] >= [7] = [true()] [or(false(), false())] = [8] > [4] = [false()] [mem(x, nil())] = [7] > [4] = [false()] [mem(x, set(y))] = [1] y + [7] >= [1] y + [7] = [=(x, y)] [mem(x, union(y, z))] = [1] y + [1] z + [7] > [1] y + [1] z + [0] = [or(mem(x, y), mem(x, z))] Further, it can be verified that all rules not oriented are covered by the weightgap condition. We are left with following problem, upon which TcT provides the certificate YES(O(1),O(1)). Weak Trs: { or(x, true()) -> true() , or(true(), y) -> true() , or(false(), false()) -> false() , mem(x, nil()) -> false() , mem(x, set(y)) -> =(x, y) , mem(x, union(y, z)) -> or(mem(x, y), mem(x, z)) } Obligation: innermost runtime complexity Answer: YES(O(1),O(1)) Empty rules are trivially bounded Hurray, we answered YES(O(1),O(n^1))