MAYBE We are left with following problem, upon which TcT provides the certificate MAYBE. Strict Trs: { active(from(X)) -> from(active(X)) , active(from(X)) -> mark(cons(X, from(s(X)))) , active(cons(X1, X2)) -> cons(active(X1), X2) , active(s(X)) -> s(active(X)) , active(sel(X1, X2)) -> sel(X1, active(X2)) , active(sel(X1, X2)) -> sel(active(X1), X2) , active(sel(s(N), cons(X, XS))) -> mark(sel(N, XS)) , active(sel(0(), cons(X, XS))) -> mark(X) , active(minus(X1, X2)) -> minus(X1, active(X2)) , active(minus(X1, X2)) -> minus(active(X1), X2) , active(minus(X, 0())) -> mark(0()) , active(minus(s(X), s(Y))) -> mark(minus(X, Y)) , active(quot(X1, X2)) -> quot(X1, active(X2)) , active(quot(X1, X2)) -> quot(active(X1), X2) , active(quot(s(X), s(Y))) -> mark(s(quot(minus(X, Y), s(Y)))) , active(quot(0(), s(Y))) -> mark(0()) , active(zWquot(X1, X2)) -> zWquot(X1, active(X2)) , active(zWquot(X1, X2)) -> zWquot(active(X1), X2) , active(zWquot(XS, nil())) -> mark(nil()) , active(zWquot(cons(X, XS), cons(Y, YS))) -> mark(cons(quot(X, Y), zWquot(XS, YS))) , active(zWquot(nil(), XS)) -> mark(nil()) , from(mark(X)) -> mark(from(X)) , from(ok(X)) -> ok(from(X)) , cons(mark(X1), X2) -> mark(cons(X1, X2)) , cons(ok(X1), ok(X2)) -> ok(cons(X1, X2)) , s(mark(X)) -> mark(s(X)) , s(ok(X)) -> ok(s(X)) , sel(X1, mark(X2)) -> mark(sel(X1, X2)) , sel(mark(X1), X2) -> mark(sel(X1, X2)) , sel(ok(X1), ok(X2)) -> ok(sel(X1, X2)) , minus(X1, mark(X2)) -> mark(minus(X1, X2)) , minus(mark(X1), X2) -> mark(minus(X1, X2)) , minus(ok(X1), ok(X2)) -> ok(minus(X1, X2)) , quot(X1, mark(X2)) -> mark(quot(X1, X2)) , quot(mark(X1), X2) -> mark(quot(X1, X2)) , quot(ok(X1), ok(X2)) -> ok(quot(X1, X2)) , zWquot(X1, mark(X2)) -> mark(zWquot(X1, X2)) , zWquot(mark(X1), X2) -> mark(zWquot(X1, X2)) , zWquot(ok(X1), ok(X2)) -> ok(zWquot(X1, X2)) , proper(from(X)) -> from(proper(X)) , proper(cons(X1, X2)) -> cons(proper(X1), proper(X2)) , proper(s(X)) -> s(proper(X)) , proper(sel(X1, X2)) -> sel(proper(X1), proper(X2)) , proper(0()) -> ok(0()) , proper(minus(X1, X2)) -> minus(proper(X1), proper(X2)) , proper(quot(X1, X2)) -> quot(proper(X1), proper(X2)) , proper(zWquot(X1, X2)) -> zWquot(proper(X1), proper(X2)) , proper(nil()) -> ok(nil()) , top(mark(X)) -> top(proper(X)) , top(ok(X)) -> top(active(X)) } Obligation: innermost runtime complexity Answer: MAYBE None of the processors succeeded. Details of failed attempt(s): ----------------------------- 1) 'empty' failed due to the following reason: Empty strict component of the problem is NOT empty. 2) 'Best' failed due to the following reason: None of the processors succeeded. Details of failed attempt(s): ----------------------------- 1) 'WithProblem (timeout of 60 seconds)' failed due to the following reason: Computation stopped due to timeout after 60.0 seconds. 2) 'Best' failed due to the following reason: None of the processors succeeded. Details of failed attempt(s): ----------------------------- 1) 'WithProblem (timeout of 30 seconds) (timeout of 60 seconds)' failed due to the following reason: Computation stopped due to timeout after 30.0 seconds. 2) 'Best' failed due to the following reason: None of the processors succeeded. Details of failed attempt(s): ----------------------------- 1) 'Polynomial Path Order (PS) (timeout of 60 seconds)' failed due to the following reason: The input cannot be shown compatible 2) 'bsearch-popstar (timeout of 60 seconds)' failed due to the following reason: The input cannot be shown compatible 3) 'Fastest (timeout of 5 seconds) (timeout of 60 seconds)' failed due to the following reason: None of the processors succeeded. Details of failed attempt(s): ----------------------------- 1) 'Bounds with minimal-enrichment and initial automaton 'match'' failed due to the following reason: match-boundness of the problem could not be verified. 2) 'Bounds with perSymbol-enrichment and initial automaton 'match'' failed due to the following reason: match-boundness of the problem could not be verified. Arrrr..