MAYBE We are left with following problem, upon which TcT provides the certificate MAYBE. Strict Trs: { active(U11(X1, X2, X3)) -> U11(active(X1), X2, X3) , active(U11(tt(), M, N)) -> mark(U12(tt(), M, N)) , active(U12(X1, X2, X3)) -> U12(active(X1), X2, X3) , active(U12(tt(), M, N)) -> mark(s(plus(N, M))) , active(s(X)) -> s(active(X)) , active(plus(X1, X2)) -> plus(X1, active(X2)) , active(plus(X1, X2)) -> plus(active(X1), X2) , active(plus(N, s(M))) -> mark(U11(tt(), M, N)) , active(plus(N, 0())) -> mark(N) , active(U21(X1, X2, X3)) -> U21(active(X1), X2, X3) , active(U21(tt(), M, N)) -> mark(U22(tt(), M, N)) , active(U22(X1, X2, X3)) -> U22(active(X1), X2, X3) , active(U22(tt(), M, N)) -> mark(plus(x(N, M), N)) , active(x(X1, X2)) -> x(X1, active(X2)) , active(x(X1, X2)) -> x(active(X1), X2) , active(x(N, s(M))) -> mark(U21(tt(), M, N)) , active(x(N, 0())) -> mark(0()) , U11(mark(X1), X2, X3) -> mark(U11(X1, X2, X3)) , U11(ok(X1), ok(X2), ok(X3)) -> ok(U11(X1, X2, X3)) , U12(mark(X1), X2, X3) -> mark(U12(X1, X2, X3)) , U12(ok(X1), ok(X2), ok(X3)) -> ok(U12(X1, X2, X3)) , s(mark(X)) -> mark(s(X)) , s(ok(X)) -> ok(s(X)) , plus(X1, mark(X2)) -> mark(plus(X1, X2)) , plus(mark(X1), X2) -> mark(plus(X1, X2)) , plus(ok(X1), ok(X2)) -> ok(plus(X1, X2)) , U21(mark(X1), X2, X3) -> mark(U21(X1, X2, X3)) , U21(ok(X1), ok(X2), ok(X3)) -> ok(U21(X1, X2, X3)) , U22(mark(X1), X2, X3) -> mark(U22(X1, X2, X3)) , U22(ok(X1), ok(X2), ok(X3)) -> ok(U22(X1, X2, X3)) , x(X1, mark(X2)) -> mark(x(X1, X2)) , x(mark(X1), X2) -> mark(x(X1, X2)) , x(ok(X1), ok(X2)) -> ok(x(X1, X2)) , proper(U11(X1, X2, X3)) -> U11(proper(X1), proper(X2), proper(X3)) , proper(tt()) -> ok(tt()) , proper(U12(X1, X2, X3)) -> U12(proper(X1), proper(X2), proper(X3)) , proper(s(X)) -> s(proper(X)) , proper(plus(X1, X2)) -> plus(proper(X1), proper(X2)) , proper(U21(X1, X2, X3)) -> U21(proper(X1), proper(X2), proper(X3)) , proper(U22(X1, X2, X3)) -> U22(proper(X1), proper(X2), proper(X3)) , proper(x(X1, X2)) -> x(proper(X1), proper(X2)) , proper(0()) -> ok(0()) , top(mark(X)) -> top(proper(X)) , top(ok(X)) -> top(active(X)) } Obligation: innermost runtime complexity Answer: MAYBE None of the processors succeeded. Details of failed attempt(s): ----------------------------- 1) 'empty' failed due to the following reason: Empty strict component of the problem is NOT empty. 2) 'Best' failed due to the following reason: None of the processors succeeded. Details of failed attempt(s): ----------------------------- 1) 'WithProblem (timeout of 60 seconds)' failed due to the following reason: Computation stopped due to timeout after 60.0 seconds. 2) 'Best' failed due to the following reason: None of the processors succeeded. Details of failed attempt(s): ----------------------------- 1) 'WithProblem (timeout of 30 seconds) (timeout of 60 seconds)' failed due to the following reason: Computation stopped due to timeout after 30.0 seconds. 2) 'Best' failed due to the following reason: None of the processors succeeded. Details of failed attempt(s): ----------------------------- 1) 'bsearch-popstar (timeout of 60 seconds)' failed due to the following reason: The input cannot be shown compatible 2) 'Polynomial Path Order (PS) (timeout of 60 seconds)' failed due to the following reason: The input cannot be shown compatible 3) 'Fastest (timeout of 5 seconds) (timeout of 60 seconds)' failed due to the following reason: None of the processors succeeded. Details of failed attempt(s): ----------------------------- 1) 'Bounds with minimal-enrichment and initial automaton 'match'' failed due to the following reason: match-boundness of the problem could not be verified. 2) 'Bounds with perSymbol-enrichment and initial automaton 'match'' failed due to the following reason: match-boundness of the problem could not be verified. Arrrr..