MAYBE We are left with following problem, upon which TcT provides the certificate MAYBE. Strict Trs: { active(zeros()) -> mark(cons(0(), zeros())) , active(cons(X1, X2)) -> cons(active(X1), X2) , active(U11(X1, X2)) -> U11(active(X1), X2) , active(U11(tt(), L)) -> mark(U12(tt(), L)) , active(U12(X1, X2)) -> U12(active(X1), X2) , active(U12(tt(), L)) -> mark(s(length(L))) , active(s(X)) -> s(active(X)) , active(length(X)) -> length(active(X)) , active(length(cons(N, L))) -> mark(U11(tt(), L)) , active(length(nil())) -> mark(0()) , active(U21(X1, X2, X3, X4)) -> U21(active(X1), X2, X3, X4) , active(U21(tt(), IL, M, N)) -> mark(U22(tt(), IL, M, N)) , active(U22(X1, X2, X3, X4)) -> U22(active(X1), X2, X3, X4) , active(U22(tt(), IL, M, N)) -> mark(U23(tt(), IL, M, N)) , active(U23(X1, X2, X3, X4)) -> U23(active(X1), X2, X3, X4) , active(U23(tt(), IL, M, N)) -> mark(cons(N, take(M, IL))) , active(take(X1, X2)) -> take(X1, active(X2)) , active(take(X1, X2)) -> take(active(X1), X2) , active(take(0(), IL)) -> mark(nil()) , active(take(s(M), cons(N, IL))) -> mark(U21(tt(), IL, M, N)) , cons(mark(X1), X2) -> mark(cons(X1, X2)) , cons(ok(X1), ok(X2)) -> ok(cons(X1, X2)) , U11(mark(X1), X2) -> mark(U11(X1, X2)) , U11(ok(X1), ok(X2)) -> ok(U11(X1, X2)) , U12(mark(X1), X2) -> mark(U12(X1, X2)) , U12(ok(X1), ok(X2)) -> ok(U12(X1, X2)) , s(mark(X)) -> mark(s(X)) , s(ok(X)) -> ok(s(X)) , length(mark(X)) -> mark(length(X)) , length(ok(X)) -> ok(length(X)) , U21(mark(X1), X2, X3, X4) -> mark(U21(X1, X2, X3, X4)) , U21(ok(X1), ok(X2), ok(X3), ok(X4)) -> ok(U21(X1, X2, X3, X4)) , U22(mark(X1), X2, X3, X4) -> mark(U22(X1, X2, X3, X4)) , U22(ok(X1), ok(X2), ok(X3), ok(X4)) -> ok(U22(X1, X2, X3, X4)) , U23(mark(X1), X2, X3, X4) -> mark(U23(X1, X2, X3, X4)) , U23(ok(X1), ok(X2), ok(X3), ok(X4)) -> ok(U23(X1, X2, X3, X4)) , take(X1, mark(X2)) -> mark(take(X1, X2)) , take(mark(X1), X2) -> mark(take(X1, X2)) , take(ok(X1), ok(X2)) -> ok(take(X1, X2)) , proper(zeros()) -> ok(zeros()) , proper(cons(X1, X2)) -> cons(proper(X1), proper(X2)) , proper(0()) -> ok(0()) , proper(U11(X1, X2)) -> U11(proper(X1), proper(X2)) , proper(tt()) -> ok(tt()) , proper(U12(X1, X2)) -> U12(proper(X1), proper(X2)) , proper(s(X)) -> s(proper(X)) , proper(length(X)) -> length(proper(X)) , proper(U21(X1, X2, X3, X4)) -> U21(proper(X1), proper(X2), proper(X3), proper(X4)) , proper(U22(X1, X2, X3, X4)) -> U22(proper(X1), proper(X2), proper(X3), proper(X4)) , proper(U23(X1, X2, X3, X4)) -> U23(proper(X1), proper(X2), proper(X3), proper(X4)) , proper(take(X1, X2)) -> take(proper(X1), proper(X2)) , proper(nil()) -> ok(nil()) , top(mark(X)) -> top(proper(X)) , top(ok(X)) -> top(active(X)) } Obligation: innermost runtime complexity Answer: MAYBE None of the processors succeeded. Details of failed attempt(s): ----------------------------- 1) 'empty' failed due to the following reason: Empty strict component of the problem is NOT empty. 2) 'Best' failed due to the following reason: None of the processors succeeded. Details of failed attempt(s): ----------------------------- 1) 'WithProblem (timeout of 60 seconds)' failed due to the following reason: Computation stopped due to timeout after 60.0 seconds. 2) 'Best' failed due to the following reason: None of the processors succeeded. Details of failed attempt(s): ----------------------------- 1) 'WithProblem (timeout of 30 seconds) (timeout of 60 seconds)' failed due to the following reason: Computation stopped due to timeout after 30.0 seconds. 2) 'Fastest (timeout of 5 seconds) (timeout of 60 seconds)' failed due to the following reason: Computation stopped due to timeout after 5.0 seconds. 3) 'Best' failed due to the following reason: None of the processors succeeded. Details of failed attempt(s): ----------------------------- 1) 'bsearch-popstar (timeout of 60 seconds)' failed due to the following reason: The input cannot be shown compatible 2) 'Polynomial Path Order (PS) (timeout of 60 seconds)' failed due to the following reason: The input cannot be shown compatible Arrrr..