MAYBE We are left with following problem, upon which TcT provides the certificate MAYBE. Strict Trs: { le(s(x), s(y)) -> le(x, y) , le(s(x), 0()) -> false() , le(0(), y) -> true() , plus(s(x), y) -> s(plus(x, y)) , plus(0(), y) -> y , times(s(x), y) -> plus(y, times(x, y)) , times(0(), y) -> 0() , log(x, s(0())) -> baseError() , log(x, 0()) -> baseError() , log(s(x), s(s(b))) -> loop(s(x), s(s(b)), s(0()), 0()) , log(0(), s(s(b))) -> logZeroError() , loop(x, s(s(b)), s(y), z) -> if(le(x, s(y)), x, s(s(b)), s(y), z) , if(false(), x, b, y, z) -> loop(x, b, times(b, y), s(z)) , if(true(), x, b, y, z) -> z } Obligation: runtime complexity Answer: MAYBE None of the processors succeeded. Details of failed attempt(s): ----------------------------- 1) 'WithProblem (timeout of 60 seconds)' failed due to the following reason: Computation stopped due to timeout after 60.0 seconds. 2) 'Best' failed due to the following reason: None of the processors succeeded. Details of failed attempt(s): ----------------------------- 1) 'WithProblem (timeout of 30 seconds) (timeout of 60 seconds)' failed due to the following reason: Computation stopped due to timeout after 30.0 seconds. 2) 'Fastest (timeout of 5 seconds) (timeout of 60 seconds)' failed due to the following reason: None of the processors succeeded. Details of failed attempt(s): ----------------------------- 1) 'Bounds with minimal-enrichment and initial automaton 'match'' failed due to the following reason: match-boundness of the problem could not be verified. 2) 'Bounds with perSymbol-enrichment and initial automaton 'match'' failed due to the following reason: match-boundness of the problem could not be verified. 3) 'Best' failed due to the following reason: None of the processors succeeded. Details of failed attempt(s): ----------------------------- 1) 'bsearch-popstar (timeout of 60 seconds)' failed due to the following reason: The processor is inapplicable, reason: Processor only applicable for innermost runtime complexity analysis 2) 'Polynomial Path Order (PS) (timeout of 60 seconds)' failed due to the following reason: The processor is inapplicable, reason: Processor only applicable for innermost runtime complexity analysis 3) 'Innermost Weak Dependency Pairs (timeout of 60 seconds)' failed due to the following reason: We add the following weak dependency pairs: Strict DPs: { le^#(s(x), s(y)) -> c_1(le^#(x, y)) , le^#(s(x), 0()) -> c_2() , le^#(0(), y) -> c_3() , plus^#(s(x), y) -> c_4(plus^#(x, y)) , plus^#(0(), y) -> c_5(y) , times^#(s(x), y) -> c_6(plus^#(y, times(x, y))) , times^#(0(), y) -> c_7() , log^#(x, s(0())) -> c_8() , log^#(x, 0()) -> c_9() , log^#(s(x), s(s(b))) -> c_10(loop^#(s(x), s(s(b)), s(0()), 0())) , log^#(0(), s(s(b))) -> c_11() , loop^#(x, s(s(b)), s(y), z) -> c_12(if^#(le(x, s(y)), x, s(s(b)), s(y), z)) , if^#(false(), x, b, y, z) -> c_13(loop^#(x, b, times(b, y), s(z))) , if^#(true(), x, b, y, z) -> c_14(z) } and mark the set of starting terms. We are left with following problem, upon which TcT provides the certificate MAYBE. Strict DPs: { le^#(s(x), s(y)) -> c_1(le^#(x, y)) , le^#(s(x), 0()) -> c_2() , le^#(0(), y) -> c_3() , plus^#(s(x), y) -> c_4(plus^#(x, y)) , plus^#(0(), y) -> c_5(y) , times^#(s(x), y) -> c_6(plus^#(y, times(x, y))) , times^#(0(), y) -> c_7() , log^#(x, s(0())) -> c_8() , log^#(x, 0()) -> c_9() , log^#(s(x), s(s(b))) -> c_10(loop^#(s(x), s(s(b)), s(0()), 0())) , log^#(0(), s(s(b))) -> c_11() , loop^#(x, s(s(b)), s(y), z) -> c_12(if^#(le(x, s(y)), x, s(s(b)), s(y), z)) , if^#(false(), x, b, y, z) -> c_13(loop^#(x, b, times(b, y), s(z))) , if^#(true(), x, b, y, z) -> c_14(z) } Strict Trs: { le(s(x), s(y)) -> le(x, y) , le(s(x), 0()) -> false() , le(0(), y) -> true() , plus(s(x), y) -> s(plus(x, y)) , plus(0(), y) -> y , times(s(x), y) -> plus(y, times(x, y)) , times(0(), y) -> 0() , log(x, s(0())) -> baseError() , log(x, 0()) -> baseError() , log(s(x), s(s(b))) -> loop(s(x), s(s(b)), s(0()), 0()) , log(0(), s(s(b))) -> logZeroError() , loop(x, s(s(b)), s(y), z) -> if(le(x, s(y)), x, s(s(b)), s(y), z) , if(false(), x, b, y, z) -> loop(x, b, times(b, y), s(z)) , if(true(), x, b, y, z) -> z } Obligation: runtime complexity Answer: MAYBE We estimate the number of application of {2,3,7,8,9,11} by applications of Pre({2,3,7,8,9,11}) = {1,5,14}. Here rules are labeled as follows: DPs: { 1: le^#(s(x), s(y)) -> c_1(le^#(x, y)) , 2: le^#(s(x), 0()) -> c_2() , 3: le^#(0(), y) -> c_3() , 4: plus^#(s(x), y) -> c_4(plus^#(x, y)) , 5: plus^#(0(), y) -> c_5(y) , 6: times^#(s(x), y) -> c_6(plus^#(y, times(x, y))) , 7: times^#(0(), y) -> c_7() , 8: log^#(x, s(0())) -> c_8() , 9: log^#(x, 0()) -> c_9() , 10: log^#(s(x), s(s(b))) -> c_10(loop^#(s(x), s(s(b)), s(0()), 0())) , 11: log^#(0(), s(s(b))) -> c_11() , 12: loop^#(x, s(s(b)), s(y), z) -> c_12(if^#(le(x, s(y)), x, s(s(b)), s(y), z)) , 13: if^#(false(), x, b, y, z) -> c_13(loop^#(x, b, times(b, y), s(z))) , 14: if^#(true(), x, b, y, z) -> c_14(z) } We are left with following problem, upon which TcT provides the certificate MAYBE. Strict DPs: { le^#(s(x), s(y)) -> c_1(le^#(x, y)) , plus^#(s(x), y) -> c_4(plus^#(x, y)) , plus^#(0(), y) -> c_5(y) , times^#(s(x), y) -> c_6(plus^#(y, times(x, y))) , log^#(s(x), s(s(b))) -> c_10(loop^#(s(x), s(s(b)), s(0()), 0())) , loop^#(x, s(s(b)), s(y), z) -> c_12(if^#(le(x, s(y)), x, s(s(b)), s(y), z)) , if^#(false(), x, b, y, z) -> c_13(loop^#(x, b, times(b, y), s(z))) , if^#(true(), x, b, y, z) -> c_14(z) } Strict Trs: { le(s(x), s(y)) -> le(x, y) , le(s(x), 0()) -> false() , le(0(), y) -> true() , plus(s(x), y) -> s(plus(x, y)) , plus(0(), y) -> y , times(s(x), y) -> plus(y, times(x, y)) , times(0(), y) -> 0() , log(x, s(0())) -> baseError() , log(x, 0()) -> baseError() , log(s(x), s(s(b))) -> loop(s(x), s(s(b)), s(0()), 0()) , log(0(), s(s(b))) -> logZeroError() , loop(x, s(s(b)), s(y), z) -> if(le(x, s(y)), x, s(s(b)), s(y), z) , if(false(), x, b, y, z) -> loop(x, b, times(b, y), s(z)) , if(true(), x, b, y, z) -> z } Weak DPs: { le^#(s(x), 0()) -> c_2() , le^#(0(), y) -> c_3() , times^#(0(), y) -> c_7() , log^#(x, s(0())) -> c_8() , log^#(x, 0()) -> c_9() , log^#(0(), s(s(b))) -> c_11() } Obligation: runtime complexity Answer: MAYBE Empty strict component of the problem is NOT empty. Arrrr..