YES(O(1),O(1)) We are left with following problem, upon which TcT provides the certificate YES(O(1),O(1)). Strict Trs: { f(g(x), g(y)) -> f(p(f(g(x), s(y))), g(s(p(x)))) , g(s(p(x))) -> p(x) , p(0()) -> g(0()) } Obligation: runtime complexity Answer: YES(O(1),O(1)) We add the following weak dependency pairs: Strict DPs: { f^#(g(x), g(y)) -> c_1(f^#(p(f(g(x), s(y))), g(s(p(x))))) , g^#(s(p(x))) -> c_2(p^#(x)) , p^#(0()) -> c_3(g^#(0())) } and mark the set of starting terms. We are left with following problem, upon which TcT provides the certificate YES(O(1),O(1)). Strict DPs: { f^#(g(x), g(y)) -> c_1(f^#(p(f(g(x), s(y))), g(s(p(x))))) , g^#(s(p(x))) -> c_2(p^#(x)) , p^#(0()) -> c_3(g^#(0())) } Strict Trs: { f(g(x), g(y)) -> f(p(f(g(x), s(y))), g(s(p(x)))) , g(s(p(x))) -> p(x) , p(0()) -> g(0()) } Obligation: runtime complexity Answer: YES(O(1),O(1)) Consider the dependency graph: 1: f^#(g(x), g(y)) -> c_1(f^#(p(f(g(x), s(y))), g(s(p(x))))) 2: g^#(s(p(x))) -> c_2(p^#(x)) -->_1 p^#(0()) -> c_3(g^#(0())) :3 3: p^#(0()) -> c_3(g^#(0())) Only the nodes {3} are reachable from nodes {3} that start derivation from marked basic terms. The nodes not reachable are removed from the problem. We are left with following problem, upon which TcT provides the certificate YES(O(1),O(1)). Strict DPs: { p^#(0()) -> c_3(g^#(0())) } Strict Trs: { f(g(x), g(y)) -> f(p(f(g(x), s(y))), g(s(p(x)))) , g(s(p(x))) -> p(x) , p(0()) -> g(0()) } Obligation: runtime complexity Answer: YES(O(1),O(1)) We estimate the number of application of {1} by applications of Pre({1}) = {}. Here rules are labeled as follows: DPs: { 1: p^#(0()) -> c_3(g^#(0())) } We are left with following problem, upon which TcT provides the certificate YES(O(1),O(1)). Strict Trs: { f(g(x), g(y)) -> f(p(f(g(x), s(y))), g(s(p(x)))) , g(s(p(x))) -> p(x) , p(0()) -> g(0()) } Weak DPs: { p^#(0()) -> c_3(g^#(0())) } Obligation: runtime complexity Answer: YES(O(1),O(1)) No rule is usable, rules are removed from the input problem. We are left with following problem, upon which TcT provides the certificate YES(O(1),O(1)). Weak DPs: { p^#(0()) -> c_3(g^#(0())) } Obligation: runtime complexity Answer: YES(O(1),O(1)) Empty rules are trivially bounded Hurray, we answered YES(O(1),O(1))