LTS Termination Proof

by AProVE

Input

Integer Transition System

Proof

1 Switch to Cooperation Termination Proof

We consider the following cutpoint-transitions:
f145_0_main_LE' f145_0_main_LE' f145_0_main_LE': x1 = x1x2 = x2
f145_0_main_LE f145_0_main_LE f145_0_main_LE: x1 = x1x2 = x2
f1_0_main_Load f1_0_main_Load f1_0_main_Load: x1 = x1x2 = x2
__init __init __init: x1 = x1x2 = x2
and for every transition t, a duplicate t is considered.

2 SCC Decomposition

We consider subproblems for each of the 1 SCC(s) of the program graph.

2.1 SCC Subproblem 1/1

Here we consider the SCC { f145_0_main_LE', f145_0_main_LE }.

2.1.1 Transition Removal

We remove transitions 2, 3, 4, 5 using the following ranking functions, which are bounded by 0.

f145_0_main_LE: −2⋅x2 + 2⋅x1
f145_0_main_LE': 2⋅x1 − 2⋅x2 − 1

2.1.2 Trivial Cooperation Program

There are no more "sharp" transitions in the cooperation program. Hence the cooperation termination is proved.

Tool configuration

AProVE