LTS Termination Proof

by AProVE

Input

Integer Transition System

Proof

1 Switch to Cooperation Termination Proof

We consider the following cutpoint-transitions:
f200_0_random_ArrayAccess f200_0_random_ArrayAccess f200_0_random_ArrayAccess: x1 = x1x2 = x2x3 = x3x4 = x4x5 = x5
f387_0_length_NULL f387_0_length_NULL f387_0_length_NULL: x1 = x1x2 = x2x3 = x3x4 = x4x5 = x5
f314_0_appendNewList_LE f314_0_appendNewList_LE f314_0_appendNewList_LE: x1 = x1x2 = x2x3 = x3x4 = x4x5 = x5
f1_0_main_Load f1_0_main_Load f1_0_main_Load: x1 = x1x2 = x2x3 = x3x4 = x4x5 = x5
f165_0_appendNewList_LE f165_0_appendNewList_LE f165_0_appendNewList_LE: x1 = x1x2 = x2x3 = x3x4 = x4x5 = x5
__init __init __init: x1 = x1x2 = x2x3 = x3x4 = x4x5 = x5
and for every transition t, a duplicate t is considered.

2 SCC Decomposition

We consider subproblems for each of the 3 SCC(s) of the program graph.

2.1 SCC Subproblem 1/3

Here we consider the SCC { f165_0_appendNewList_LE }.

2.1.1 Transition Removal

We remove transitions 4, 5 using the following ranking functions, which are bounded by 0.

f165_0_appendNewList_LE: x4

2.1.2 Trivial Cooperation Program

There are no more "sharp" transitions in the cooperation program. Hence the cooperation termination is proved.

2.2 SCC Subproblem 2/3

Here we consider the SCC { f314_0_appendNewList_LE }.

2.2.1 Transition Removal

We remove transitions 7, 8 using the following ranking functions, which are bounded by 0.

f314_0_appendNewList_LE: x2

2.2.2 Trivial Cooperation Program

There are no more "sharp" transitions in the cooperation program. Hence the cooperation termination is proved.

2.3 SCC Subproblem 3/3

Here we consider the SCC { f387_0_length_NULL }.

2.3.1 Transition Removal

We remove transition 10 using the following ranking functions, which are bounded by 0.

f387_0_length_NULL: x1

2.3.2 Trivial Cooperation Program

There are no more "sharp" transitions in the cooperation program. Hence the cooperation termination is proved.

Tool configuration

AProVE