LTS Termination Proof

by AProVE

Input

Integer Transition System

Proof

1 Switch to Cooperation Termination Proof

We consider the following cutpoint-transitions:
f1_0_main_New f1_0_main_New f1_0_main_New: x1 = x1x2 = x2x3 = x3x4 = x4x5 = x5x6 = x6
f83_0_doSum_NONNULL f83_0_doSum_NONNULL f83_0_doSum_NONNULL: x1 = x1x2 = x2x3 = x3x4 = x4x5 = x5x6 = x6
f160_0_factorial_GT f160_0_factorial_GT f160_0_factorial_GT: x1 = x1x2 = x2x3 = x3x4 = x4x5 = x5x6 = x6
__init __init __init: x1 = x1x2 = x2x3 = x3x4 = x4x5 = x5x6 = x6
and for every transition t, a duplicate t is considered.

2 SCC Decomposition

We consider subproblems for each of the 1 SCC(s) of the program graph.

2.1 SCC Subproblem 1/1

Here we consider the SCC { f83_0_doSum_NONNULL, f160_0_factorial_GT }.

2.1.1 Transition Removal

We remove transitions 2, 3 using the following ranking functions, which are bounded by 0.

f83_0_doSum_NONNULL: 1 + 2⋅x1
f160_0_factorial_GT: 2⋅x1

2.1.2 Transition Removal

We remove transition 4 using the following ranking functions, which are bounded by 0.

f160_0_factorial_GT: x4 + x5

2.1.3 Trivial Cooperation Program

There are no more "sharp" transitions in the cooperation program. Hence the cooperation termination is proved.

Tool configuration

AProVE