by AProVE
f1_0_main_Load | 1 | f152_0_gcd_EQ: | x1 = _arg1 ∧ x2 = _arg2 ∧ x1 = _arg1P ∧ x2 = _arg2P ∧ 0 ≤ _arg1 − 1 ∧ −1 ≤ _arg1P − 1 ∧ −1 ≤ _arg2 − 1 ∧ −1 ≤ _arg2P − 1 | |
f152_0_gcd_EQ | 2 | f198_0_mod_LE: | x1 = _x ∧ x2 = _x1 ∧ x1 = _x2 ∧ x2 = _x3 ∧ _x1 = _x3 ∧ _x = _x2 ∧ 0 ≤ _x1 − 1 ∧ −1 ≤ _x − 1 ∧ _x ≤ _x1 − 1 | |
f152_0_gcd_EQ | 3 | f198_0_mod_LE: | x1 = _x4 ∧ x2 = _x5 ∧ x1 = _x6 ∧ x2 = _x7 ∧ _x5 = _x7 ∧ _x4 = _x6 ∧ 0 ≤ _x5 − 1 ∧ −1 ≤ _x4 − 1 ∧ _x5 ≤ _x4 − 1 | |
f198_0_mod_LE | 4 | f198_0_mod_LE: | x1 = _x8 ∧ x2 = _x9 ∧ x1 = _x10 ∧ x2 = _x11 ∧ _x9 = _x11 ∧ _x8 − _x9 = _x10 ∧ 0 ≤ _x9 − 1 ∧ 0 ≤ _x8 − 1 ∧ _x9 ≤ _x8 − 1 | |
f152_0_gcd_EQ | 5 | f152_0_gcd_EQ: | x1 = _x12 ∧ x2 = _x13 ∧ x1 = _x14 ∧ x2 = _x15 ∧ 0 = _x15 ∧ _x12 = _x14 ∧ _x12 = _x13 ∧ 0 ≤ _x12 − 1 | |
f198_0_mod_LE | 6 | f152_0_gcd_EQ: | x1 = _x16 ∧ x2 = _x17 ∧ x1 = _x18 ∧ x2 = _x19 ∧ _x16 = _x19 ∧ _x17 = _x18 ∧ _x16 ≤ _x17 − 1 | |
__init | 7 | f1_0_main_Load: | x1 = _x20 ∧ x2 = _x21 ∧ x1 = _x22 ∧ x2 = _x23 ∧ 0 ≤ 0 |
f1_0_main_Load | f1_0_main_Load | : | x1 = x1 ∧ x2 = x2 |
f152_0_gcd_EQ | f152_0_gcd_EQ | : | x1 = x1 ∧ x2 = x2 |
f198_0_mod_LE | f198_0_mod_LE | : | x1 = x1 ∧ x2 = x2 |
__init | __init | : | x1 = x1 ∧ x2 = x2 |
We consider subproblems for each of the 1 SCC(s) of the program graph.
Here we consider the SCC {
, }.We remove transitions
, using the following ranking functions, which are bounded by 0.: | −2 + x1 + x2 |
: | −2 + x1 + x2 |
We remove transitions
, using the following ranking functions, which are bounded by 0.: | − x1 + x2 |
: | −1 − x1 + x2 |
We remove transition
using the following ranking functions, which are bounded by 0.: | 0 |
: | −1 |
There are no more "sharp" transitions in the cooperation program. Hence the cooperation termination is proved.