LTS Termination Proof

by AProVE

Input

Integer Transition System

Proof

1 Switch to Cooperation Termination Proof

We consider the following cutpoint-transitions:
f297_0_createIntList_Return f297_0_createIntList_Return f297_0_createIntList_Return: x1 = x1x2 = x2
f508_0_random_ArrayAccess f508_0_random_ArrayAccess f508_0_random_ArrayAccess: x1 = x1x2 = x2
f698_0_nth_LE f698_0_nth_LE f698_0_nth_LE: x1 = x1x2 = x2
f746_0_main_LE f746_0_main_LE f746_0_main_LE: x1 = x1x2 = x2
f1_0_main_Load f1_0_main_Load f1_0_main_Load: x1 = x1x2 = x2
f658_0_createIntList_LE f658_0_createIntList_LE f658_0_createIntList_LE: x1 = x1x2 = x2
__init __init __init: x1 = x1x2 = x2
and for every transition t, a duplicate t is considered.

2 SCC Decomposition

We consider subproblems for each of the 3 SCC(s) of the program graph.

2.1 SCC Subproblem 1/3

Here we consider the SCC { f658_0_createIntList_LE }.

2.1.1 Transition Removal

We remove transition 8 using the following ranking functions, which are bounded by 0.

f658_0_createIntList_LE: x1

2.1.2 Trivial Cooperation Program

There are no more "sharp" transitions in the cooperation program. Hence the cooperation termination is proved.

2.2 SCC Subproblem 2/3

Here we consider the SCC { f698_0_nth_LE }.

2.2.1 Transition Removal

We remove transition 5 using the following ranking functions, which are bounded by 0.

f698_0_nth_LE: x2

2.2.2 Trivial Cooperation Program

There are no more "sharp" transitions in the cooperation program. Hence the cooperation termination is proved.

2.3 SCC Subproblem 3/3

Here we consider the SCC { f746_0_main_LE }.

2.3.1 Transition Removal

We remove transition 6 using the following ranking functions, which are bounded by 0.

f746_0_main_LE: x1

2.3.2 Trivial Cooperation Program

There are no more "sharp" transitions in the cooperation program. Hence the cooperation termination is proved.

Tool configuration

AProVE