LTS Termination Proof

by AProVE

Input

Integer Transition System

Proof

1 Switch to Cooperation Termination Proof

We consider the following cutpoint-transitions:
f1079_0_mirror_NULL f1079_0_mirror_NULL f1079_0_mirror_NULL: x1 = x1x2 = x2x3 = x3x4 = x4x5 = x5x6 = x6
f1039_0_createTree_GE f1039_0_createTree_GE f1039_0_createTree_GE: x1 = x1x2 = x2x3 = x3x4 = x4x5 = x5x6 = x6
f350_0_createTree_Return f350_0_createTree_Return f350_0_createTree_Return: x1 = x1x2 = x2x3 = x3x4 = x4x5 = x5x6 = x6
f1_0_main_Load f1_0_main_Load f1_0_main_Load: x1 = x1x2 = x2x3 = x3x4 = x4x5 = x5x6 = x6
f1061_0_main_InvokeMethod f1061_0_main_InvokeMethod f1061_0_main_InvokeMethod: x1 = x1x2 = x2x3 = x3x4 = x4x5 = x5x6 = x6
f499_0_createTree_GT f499_0_createTree_GT f499_0_createTree_GT: x1 = x1x2 = x2x3 = x3x4 = x4x5 = x5x6 = x6
__init __init __init: x1 = x1x2 = x2x3 = x3x4 = x4x5 = x5x6 = x6
f1400_0_mirror_FieldAccess f1400_0_mirror_FieldAccess f1400_0_mirror_FieldAccess: x1 = x1x2 = x2x3 = x3x4 = x4x5 = x5x6 = x6
and for every transition t, a duplicate t is considered.

2 SCC Decomposition

We consider subproblems for each of the 2 SCC(s) of the program graph.

2.1 SCC Subproblem 1/2

Here we consider the SCC { f1079_0_mirror_NULL, f1400_0_mirror_FieldAccess }.

2.1.1 Transition Removal

We remove transitions 9, 10, 13, 12, 11 using the following ranking functions, which are bounded by 0.

f1079_0_mirror_NULL: x1
f1400_0_mirror_FieldAccess: −1 + x1

2.1.2 Trivial Cooperation Program

There are no more "sharp" transitions in the cooperation program. Hence the cooperation termination is proved.

2.2 SCC Subproblem 2/2

Here we consider the SCC { f1039_0_createTree_GE, f499_0_createTree_GT }.

2.2.1 Transition Removal

We remove transitions 5, 6 using the following ranking functions, which are bounded by 0.

f499_0_createTree_GT: 1 + x1
f1039_0_createTree_GE: x1

2.2.2 Transition Removal

We remove transitions 7, 8 using the following ranking functions, which are bounded by 0.

f1039_0_createTree_GE: x3 + x4

2.2.3 Trivial Cooperation Program

There are no more "sharp" transitions in the cooperation program. Hence the cooperation termination is proved.

Tool configuration

AProVE