LTS Termination Proof

by AProVE

Input

Integer Transition System

Proof

1 Switch to Cooperation Termination Proof

We consider the following cutpoint-transitions:
f731_0_random_ArrayAccess f731_0_random_ArrayAccess f731_0_random_ArrayAccess: x1 = x1x2 = x2x3 = x3x4 = x4
f322_0_createTree_Return f322_0_createTree_Return f322_0_createTree_Return: x1 = x1x2 = x2x3 = x3x4 = x4
f750_0_random_ArrayAccess f750_0_random_ArrayAccess f750_0_random_ArrayAccess: x1 = x1x2 = x2x3 = x3x4 = x4
f512_0_createNode_Return f512_0_createNode_Return f512_0_createNode_Return: x1 = x1x2 = x2x3 = x3x4 = x4
f1317_0_mirror_NULL f1317_0_mirror_NULL f1317_0_mirror_NULL: x1 = x1x2 = x2x3 = x3x4 = x4
f1551_0_createTree_LE f1551_0_createTree_LE f1551_0_createTree_LE: x1 = x1x2 = x2x3 = x3x4 = x4
f1_0_main_Load f1_0_main_Load f1_0_main_Load: x1 = x1x2 = x2x3 = x3x4 = x4
f477_0_createNode_Return f477_0_createNode_Return f477_0_createNode_Return: x1 = x1x2 = x2x3 = x3x4 = x4
__init __init __init: x1 = x1x2 = x2x3 = x3x4 = x4
and for every transition t, a duplicate t is considered.

2 SCC Decomposition

We consider subproblems for each of the 2 SCC(s) of the program graph.

2.1 SCC Subproblem 1/2

Here we consider the SCC { f1551_0_createTree_LE }.

2.1.1 Transition Removal

We remove transitions 10, 11, 12 using the following ranking functions, which are bounded by 0.

f1551_0_createTree_LE: x2

2.1.2 Trivial Cooperation Program

There are no more "sharp" transitions in the cooperation program. Hence the cooperation termination is proved.

2.2 SCC Subproblem 2/2

Here we consider the SCC { f1317_0_mirror_NULL }.

2.2.1 Transition Removal

We remove transition 3 using the following ranking functions, which are bounded by 0.

f1317_0_mirror_NULL: x1

2.2.2 Trivial Cooperation Program

There are no more "sharp" transitions in the cooperation program. Hence the cooperation termination is proved.

Tool configuration

AProVE