by AProVE
f1_0_main_Load | 1 | f142_0_main_LE: | x1 = _arg1 ∧ x2 = _arg2 ∧ x1 = _arg1P ∧ x2 = _arg2P ∧ 0 ≤ _arg1 − 1 ∧ −1 ≤ _arg2P − 1 ∧ −1 ≤ _arg2 − 1 ∧ −1 ≤ _arg1P − 1 | |
f142_0_main_LE | 2 | f194_0_main_LE: | x1 = _x ∧ x2 = _x1 ∧ x1 = _x2 ∧ x2 = _x3 ∧ _x = _x3 ∧ _x1 = _x2 ∧ 0 ≤ _x − 1 ∧ 0 ≤ _x1 − 1 ∧ _x1 ≤ _x | |
f142_0_main_LE | 3 | f209_0_main_LE: | x1 = _x4 ∧ x2 = _x5 ∧ x1 = _x6 ∧ x2 = _x7 ∧ _x5 = _x7 ∧ _x4 = _x6 ∧ 0 ≤ _x4 − 1 ∧ 0 ≤ _x5 − 1 ∧ _x4 ≤ _x5 − 1 | |
f194_0_main_LE | 4 | f142_0_main_LE: | x1 = _x8 ∧ x2 = _x9 ∧ x1 = _x10 ∧ x2 = _x11 ∧ _x8 = _x11 ∧ 0 = _x10 ∧ 0 = _x9 | |
f194_0_main_LE | 5 | f194_0_main_LE: | x1 = _x12 ∧ x2 = _x13 ∧ x1 = _x14 ∧ x2 = _x15 ∧ _x13 − 1 = _x15 ∧ _x12 = _x14 ∧ 0 ≤ _x13 − 1 | |
f209_0_main_LE | 6 | f142_0_main_LE: | x1 = _x16 ∧ x2 = _x17 ∧ x1 = _x18 ∧ x2 = _x19 ∧ 0 = _x19 ∧ _x16 = _x18 ∧ 0 = _x17 | |
f209_0_main_LE | 7 | f209_0_main_LE: | x1 = _x20 ∧ x2 = _x21 ∧ x1 = _x22 ∧ x2 = _x23 ∧ _x21 − 1 = _x23 ∧ _x20 = _x22 ∧ 0 ≤ _x21 − 1 | |
__init | 8 | f1_0_main_Load: | x1 = _x24 ∧ x2 = _x25 ∧ x1 = _x26 ∧ x2 = _x27 ∧ 0 ≤ 0 |
f194_0_main_LE | f194_0_main_LE | : | x1 = x1 ∧ x2 = x2 |
f142_0_main_LE | f142_0_main_LE | : | x1 = x1 ∧ x2 = x2 |
f1_0_main_Load | f1_0_main_Load | : | x1 = x1 ∧ x2 = x2 |
f209_0_main_LE | f209_0_main_LE | : | x1 = x1 ∧ x2 = x2 |
__init | __init | : | x1 = x1 ∧ x2 = x2 |
We consider subproblems for each of the 1 SCC(s) of the program graph.
Here we consider the SCC {
, , }.We remove transitions
, using the following ranking functions, which are bounded by 0.: | −1 + 3⋅x1 |
: | 1 + x2 |
: | −1 + 3⋅x1 |
We remove transitions
, , using the following ranking functions, which are bounded by 0.: | −5 + 4⋅x2 |
: | −5 + 4⋅x1 |
: | x2 |
We remove transition
using the following ranking functions, which are bounded by 0.: | 0 |
: | −1 |
There are no more "sharp" transitions in the cooperation program. Hence the cooperation termination is proved.